Math Problem Statement

Que - 31 Directions (31-35): Study the following passage carefully and answer the questions given below. The data given below is about number of shoes and bags sold by four different stores. Total number of bags sold by all four stores is 514 which is 50 more than sum of total number of items sold by N and P. Number of shoes sold by P is 4 more than half of number of shoes sold by M. Number of bags sold by O is 150. The ratio of number of bags to number of shoes sold by O is (p+2):(1.5q+p). Number of bags sold by N is 33.33% less than number of shoes sold by N and number of bags sold by P is 2(p+q) less than number of bags sold by O.Total number of items sold by O is 330 which 42 more than total number of items sold by M. Number of shoes sold by N is 12.5% more than number of bags sold by M

Solution

Let's break down the information from the passage step by step.

Key Variables:

Let:

  • MsM_s = Number of shoes sold by M
  • NsN_s = Number of shoes sold by N
  • OsO_s = Number of shoes sold by O
  • PsP_s = Number of shoes sold by P
  • MbM_b = Number of bags sold by M
  • NbN_b = Number of bags sold by N
  • ObO_b = Number of bags sold by O
  • PbP_b = Number of bags sold by P

Key Information:

  1. Total Bags Sold: Mb+Nb+Ob+Pb=514M_b + N_b + O_b + P_b = 514 Total number of bags sold by all four stores is 514, and this is 50 more than the total number of items sold by N and P. This implies: (Ns+Nb)+(Ps+Pb)=51450=464(N_s + N_b) + (P_s + P_b) = 514 - 50 = 464

  2. Shoes Sold by P: The number of shoes sold by P is 4 more than half the number of shoes sold by M: Ps=Ms2+4P_s = \frac{M_s}{2} + 4

  3. Bags Sold by O: The number of bags sold by O is given as: Ob=150O_b = 150

  4. Ratio for O: The ratio of the number of bags to the number of shoes sold by O is (p+2):(1.5q+p)(p+2):(1.5q+p), where the exact values of pp and qq are not given. We’ll hold this information for now.

  5. Bags Sold by N: The number of bags sold by N is 33.33% less than the number of shoes sold by N: Nb=Ns33.33100×Ns=23NsN_b = N_s - \frac{33.33}{100} \times N_s = \frac{2}{3} N_s

  6. Bags Sold by P: The number of bags sold by P is 2(p+q)2(p+q) less than the number of bags sold by O: Pb=Ob2(p+q)=1502(p+q)P_b = O_b - 2(p+q) = 150 - 2(p+q)

  7. Total Items Sold by O: The total number of items sold by O is 330, which is 42 more than the total number of items sold by M: Os+Ob=330O_s + O_b = 330 Ms+Mb=33042=288M_s + M_b = 330 - 42 = 288

  8. Shoes Sold by N: The number of shoes sold by N is 12.5% more than the number of bags sold by M: Ns=Mb+12.5100×Mb=1.125×MbN_s = M_b + \frac{12.5}{100} \times M_b = 1.125 \times M_b

Step-by-Step Approach:

We have multiple variables and equations. Let's solve them systematically.

  • Start by solving for OsO_s using Os+Ob=330O_s + O_b = 330: Os+150=330Os=180O_s + 150 = 330 \quad \Rightarrow \quad O_s = 180

  • Next, use the total number of items sold by M to set up an equation for Ms+Mb=288M_s + M_b = 288.

We can continue solving this system of equations to find the exact values of MsM_s, NsN_s, PsP_s, etc., by substituting one into the other.

Would you like me to proceed with the detailed calculations?

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Math Problem Analysis

Mathematical Concepts

Algebra
Percentages
Ratios
Linear Equations

Formulas

Total number of items: M_s + M_b, N_s + N_b, O_s + O_b, P_s + P_b
Percentage decrease: N_b = N_s - (33.33% × N_s)
Proportions: O_b/O_s = (p+2):(1.5q+p)
Linear equations for relationships between quantities

Theorems

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Suitable Grade Level

Grades 9-11