https://file.aiquickdraw.com/mathbot/file/1726456913821e2zer68b.jpg

To determine the acceleration at 8 seconds, we need to analyze the velocity vs. time graph. Acceleration is the rate of change of velocity, so it can be found by calculating the slope of the velocity-time graph.

Let's break it down:

1. **At 8 seconds**, the graph shows the velocity to be around **-3 m/s**.
2. Between **6 and 9 seconds**, the velocity changes from **0 m/s** to **-4 m/s**.

The slope (acceleration) over this period is calculated by:

\[
\text{Acceleration} = \frac{\Delta v}{\Delta t} = \frac{-4 - 0}{9 - 6} = \frac{-4}{3} \text{ m/s}^2 = -\frac{4}{3} \text{ m/s}^2
\]

Thus, the acceleration at 8 seconds is:

\[
\boxed{-\frac{4}{3} \, \text{m/s}^2}
\]

Would you like further details or explanations?

Here are 5 related questions:
1. What is the total displacement during the 9-second interval?
2. How would you calculate the average velocity over the entire interval?
3. What is the object's position at 9 seconds if it started at 10 m?
4. How would you describe the motion from 2 to 5 seconds?
5. Can you determine the maximum acceleration in the graph?

**Tip**: Remember, in a velocity-time graph, the slope at any point gives the acceleration!

This problem involves finding the acceleration at 8 seconds from a velocity-time graph. The velocity changes from 0 m/s to -4 m/s between 6 and 9 seconds, leading to an acceleration of -4/3 m/s². This concept covers key kinematics principles.

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