To calculate the average acceleration during the time interval from 0 seconds to 10 seconds, we need to use the formula for average acceleration:

$\text{Average acceleration} = \frac{\Delta v}{\Delta t}$

where:

• $\Delta v$ is the change in velocity over the time interval.
• $\Delta t$ is the change in time.

Step-by-Step Calculation:

1. Initial velocity at $t = 0$ seconds (Point O):
   From the graph, the velocity is 0 meters/second.

2. Velocity at $t = 10$ seconds (Point Q):
   At $t = 10$ seconds, the velocity is 5 meters/second.

3. Change in velocity ($\Delta v$):
   $\Delta v = v_{\text{final}} - v_{\text{initial}} = 5 - 0 = 5 \, \text{m/s}$

4. Change in time ($\Delta t$):
   $\Delta t = 10 \, \text{seconds} - 0 \, \text{seconds} = 10 \, \text{seconds}$

5. Average acceleration:
   $\text{Average acceleration} = \frac{5 \, \text{m/s}}{10 \, \text{seconds}} = 0.5 \, \text{m/s}^2$

Final Answer:

The average acceleration during the time interval from $0$ seconds to $10$ seconds is:

$0.5 \, \text{m/s}^2$

Would you like further details or have other questions?

5 Related Questions:

1. What is the acceleration from $t = 0$ to $t = 4$ seconds?
2. How do you calculate the total displacement over the entire 16 seconds?
3. What is the average velocity during the same 0 to 10 seconds interval?
4. What is the acceleration from $t = 10$ to $t = 14$ seconds?
5. How does instantaneous acceleration differ from average acceleration?

Tip: Pay close attention to different segments in velocity-time graphs; slopes in these graphs directly give you acceleration.