Math Problem Statement

What is a possible absolute value inequality to represent βˆ’1 ≀ π‘₯ ≀ 5?

Solution

The inequality βˆ’1≀x≀5-1 \leq x \leq 5 can be represented as an absolute value inequality.

First, recognize that this inequality can be rewritten in a centered form around some midpoint. The midpoint between βˆ’1-1 and 55 is:

Midpoint=βˆ’1+52=2\text{Midpoint} = \frac{-1 + 5}{2} = 2

Now, the distance from the midpoint 22 to either endpoint (such as βˆ’1-1 or 55) is:

Distance=5βˆ’2=3\text{Distance} = 5 - 2 = 3

This leads to the absolute value inequality:

∣xβˆ’2βˆ£β‰€3|x - 2| \leq 3

This inequality says that the distance between xx and 22 is at most 33, which is equivalent to the original inequality βˆ’1≀x≀5-1 \leq x \leq 5.

Would you like further details or have any questions?

Here are 5 related questions:

  1. How do you solve absolute value inequalities?
  2. What is the difference between strict and non-strict inequalities?
  3. Can an absolute value inequality ever represent two separate intervals?
  4. How would the inequality change if it were βˆ’1<x<5-1 < x < 5?
  5. How does graphing absolute value inequalities work?

Tip: Always check if you can express a compound inequality as an absolute value inequalityβ€”it can simplify solving the problem.

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Math Problem Analysis

Mathematical Concepts

Algebra
Absolute Value Inequalities
Linear Inequalities

Formulas

|x - midpoint| ≀ distance

Theorems

Absolute Value Inequality Theorem

Suitable Grade Level

Grades 9-11