Math Problem Statement

Write an absolute value inequality for the graph below. Use x for your variable.

Solution

The graph shows a number line with the shaded region between -6 and 5, inclusive of the endpoints. To express this graph as an absolute value inequality, we need to define an inequality that describes the distance of the variable xx from the midpoint of the interval.

Steps:

  1. The endpoints are at 6-6 and 55, and the midpoint between them is: Midpoint=6+52=12\text{Midpoint} = \frac{-6 + 5}{2} = -\frac{1}{2}

  2. The distance from the midpoint 12-\frac{1}{2} to either endpoint (which is the same for both sides) is: Distance=5(12)=5+12=112\text{Distance} = 5 - \left( -\frac{1}{2} \right) = 5 + \frac{1}{2} = \frac{11}{2}

  3. The absolute value inequality for this situation describes all values of xx that are within 112\frac{11}{2} units of 12-\frac{1}{2}: x+12112|x + \frac{1}{2}| \leq \frac{11}{2}

Final Answer:

The absolute value inequality for the graph is: x+12112|x + \frac{1}{2}| \leq \frac{11}{2}

This inequality represents all values of xx between 6-6 and 55.

Do you want more details or have any questions?

Here are 5 related questions to think about:

  1. How would the inequality change if the endpoints were not included?
  2. Can you express this inequality as a compound inequality instead of using absolute value?
  3. What happens to the inequality if you shift the graph by 2 units to the right?
  4. How would you solve this inequality algebraically to get the interval notation?
  5. Can this inequality be applied to real-world scenarios involving distances?

Tip: When working with absolute value inequalities, remember that the inequality symbol (less than or greater than) tells you whether you're dealing with a range of values within a specific distance (for \leq) or beyond a certain distance (for \geq).

Ask a new question for Free

By Image

Drop file here or Click Here to upload

Math Problem Analysis

Mathematical Concepts

Absolute Value Inequalities
Algebra
Number Line

Formulas

|x - midpoint| ≤ distance

Theorems

Absolute Value Theorem

Suitable Grade Level

Grades 8-10