Math Problem Statement

\frac{1}{2}\left|2x+1\right|=\left|-4+1\right|

Solution

Let's solve the equation step by step:

The equation is:

122x+1=4+1\frac{1}{2}\left|2x+1\right|=\left|-4+1\right|

  1. Simplify the absolute value on the right side:

4+1=3=3\left|-4 + 1\right| = \left|-3\right| = 3

So the equation becomes:

122x+1=3\frac{1}{2}\left|2x + 1\right| = 3

  1. Multiply both sides by 2 to eliminate the fraction:

2x+1=6\left|2x + 1\right| = 6

  1. Solve the absolute value equation:

The equation 2x+1=6\left|2x + 1\right| = 6 can be split into two cases:

Case 1: 2x+1=62x + 1 = 6

2x=612x = 6 - 1 2x=52x = 5 x=52x = \frac{5}{2}

Case 2: 2x+1=62x + 1 = -6

2x=612x = -6 - 1 2x=72x = -7 x=72x = \frac{-7}{2}

Thus, the solutions are:

x=52orx=72x = \frac{5}{2} \quad \text{or} \quad x = \frac{-7}{2}

Final Answer:

x=52orx=72x = \frac{5}{2} \quad \text{or} \quad x = \frac{-7}{2}

Would you like more details on any step or have any questions?

Related Questions:

  1. How do you solve absolute value inequalities?
  2. What is the difference between solving absolute value equations and inequalities?
  3. Can absolute value equations have more than two solutions?
  4. How does multiplying both sides of an equation by a fraction affect the solution?
  5. What happens if there is no solution to an absolute value equation?

Tip: When dealing with absolute value equations, always consider both the positive and negative scenarios to capture all possible solutions.

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Math Problem Analysis

Mathematical Concepts

Algebra
Absolute Value Equations

Formulas

|A| = B implies A = B or A = -B

Theorems

Absolute Value Theorem

Suitable Grade Level

Grades 9-11