Math Problem Statement

In a random sample of 25 ​people, the mean commute time to work was 30.2 minutes and the standard deviation was 7.1 minutes. Assume the population is normally distributed and use a​ t-distribution to construct a 80​% confidence interval for the population mean

Solution

To construct an 80% confidence interval for the population mean, we will use the t-distribution since the sample size is small (n=25n = 25), and we are given the sample's mean and standard deviation.

Given data:

  • Sample mean (xˉ\bar{x}) = 30.2 minutes
  • Sample standard deviation (ss) = 7.1 minutes
  • Sample size (nn) = 25
  • Confidence level = 80%

Steps:

  1. Determine the degrees of freedom (df): df=n1=251=24\text{df} = n - 1 = 25 - 1 = 24

  2. Find the critical value tα/2t_{\alpha/2}: For an 80% confidence interval, the area in each tail is α=10.80=0.20\alpha = 1 - 0.80 = 0.20. Since it’s a two-tailed test, the area in each tail is α/2=0.10\alpha/2 = 0.10.

    Using a t-table or a calculator to find t0.10t_{0.10} with 24 degrees of freedom, the critical value t0.10t_{0.10} is approximately 1.711.

  3. Calculate the standard error (SE) of the mean: The standard error of the mean is given by: SE=sn=7.125=7.15=1.42SE = \frac{s}{\sqrt{n}} = \frac{7.1}{\sqrt{25}} = \frac{7.1}{5} = 1.42

  4. Construct the confidence interval: The confidence interval is given by: CI=xˉ±tα/2×SE\text{CI} = \bar{x} \pm t_{\alpha/2} \times SE Substituting the values: CI=30.2±1.711×1.42\text{CI} = 30.2 \pm 1.711 \times 1.42 CI=30.2±2.42\text{CI} = 30.2 \pm 2.42

  5. Final confidence interval: CI=(30.22.42,30.2+2.42)\text{CI} = (30.2 - 2.42, 30.2 + 2.42) CI=(27.78,32.62)\text{CI} = (27.78, 32.62)

Conclusion:

The 80% confidence interval for the population mean commute time is approximately (27.78 minutes, 32.62 minutes).


Would you like a further explanation of any steps, or do you have any other questions?

Here are some related questions you might explore:

  1. How does changing the confidence level affect the width of the confidence interval?
  2. What would the confidence interval look like if we used a 95% confidence level instead?
  3. How can we calculate the margin of error for the given confidence interval?
  4. What is the difference between using the t-distribution and the z-distribution for confidence intervals?
  5. How would the confidence interval change if the sample size was increased to 50?

Tip: As sample size increases, the standard error decreases, which leads to a narrower confidence interval.

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Math Problem Analysis

Mathematical Concepts

Statistics
Confidence Intervals
t-Distribution

Formulas

Confidence Interval Formula: CI = x̄ ± t(α/2) * (s / √n)
Standard Error Formula: SE = s / √n

Theorems

t-Distribution Theorem
Central Limit Theorem

Suitable Grade Level

Undergraduate or Advanced High School (Grades 11-12)