Math Problem Statement

Determine the Z-transform and region-of-convergence (ROC) of the following signal: x[n]=−(1/​3)^n u[n]−(1/2​)^n u[-n−1]

Solution

We are given the signal:

[ x[n] = -\left(\frac{1}{3}\right)^n u[n] - \left(\frac{1}{2}\right)^n u[-n-1] ]

where u[n]u[n] is the unit step function. We need to determine the Z-transform X(z)X(z) of this signal and its region of convergence (ROC).

Step 1: Split the signal

We can split the signal into two parts:

  • The first part is x1[n]=(13)nu[n]x_1[n] = -\left(\frac{1}{3}\right)^n u[n].
  • The second part is x2[n]=(12)nu[n1]x_2[n] = -\left(\frac{1}{2}\right)^n u[-n-1].

Step 2: Z-transform of x1[n]x_1[n]

The signal x1[n]=(13)nu[n]x_1[n] = -\left(\frac{1}{3}\right)^n u[n] is a right-sided signal (defined for n0n \geq 0). The Z-transform of a general right-sided signal anu[n]a^n u[n] is given by:

Z{anu[n]}=11az1,z>a\mathcal{Z}\left\{a^n u[n]\right\} = \frac{1}{1 - az^{-1}}, \quad |z| > |a|

For x1[n]=(13)nu[n]x_1[n] = -\left(\frac{1}{3}\right)^n u[n], the Z-transform is:

X1(z)=1113z1=zz13,z>13X_1(z) = -\frac{1}{1 - \frac{1}{3}z^{-1}} = -\frac{z}{z - \frac{1}{3}}, \quad |z| > \frac{1}{3}

Step 3: Z-transform of x2[n]x_2[n]

The signal x2[n]=(12)nu[n1]x_2[n] = -\left(\frac{1}{2}\right)^n u[-n-1] is a left-sided signal (defined for n1n \leq -1). The Z-transform of a general left-sided signal anu[n1]a^n u[-n-1] is given by:

Z{anu[n1]}=11az1,z<a\mathcal{Z}\left\{a^n u[-n-1]\right\} = \frac{1}{1 - az^{-1}}, \quad |z| < |a|

For x2[n]=(12)nu[n1]x_2[n] = -\left(\frac{1}{2}\right)^n u[-n-1], the Z-transform is:

X2(z)=1112z1=zz12,z<12X_2(z) = -\frac{1}{1 - \frac{1}{2}z^{-1}} = -\frac{z}{z - \frac{1}{2}}, \quad |z| < \frac{1}{2}

Step 4: Total Z-transform

The total Z-transform X(z)X(z) is the sum of the Z-transforms of x1[n]x_1[n] and x2[n]x_2[n]:

X(z)=X1(z)+X2(z)=zz13zz12X(z) = X_1(z) + X_2(z) = -\frac{z}{z - \frac{1}{3}} - \frac{z}{z - \frac{1}{2}}

Step 5: Region of Convergence (ROC)

The ROC of the signal is determined by the individual ROCs of the two components:

  • For X1(z)X_1(z), the ROC is z>13|z| > \frac{1}{3}.
  • For X2(z)X_2(z), the ROC is z<12|z| < \frac{1}{2}.

Therefore, the total ROC is the intersection of these two regions:

13<z<12\frac{1}{3} < |z| < \frac{1}{2}

Final Answer:

The Z-transform of the signal is:

X(z)=zz13zz12X(z) = -\frac{z}{z - \frac{1}{3}} - \frac{z}{z - \frac{1}{2}}

The region of convergence (ROC) is:

13<z<12\frac{1}{3} < |z| < \frac{1}{2}

Would you like further details or explanations on any step?


Here are 5 related questions you might explore next:

  1. How does the ROC affect the stability of a system?
  2. How would the ROC change if u[n1]u[-n-1] were replaced with u[n+1]u[n+1]?
  3. What is the inverse Z-transform of X(z)X(z)?
  4. How does the Z-transform relate to the Fourier transform?
  5. How can we determine the poles and zeros from the Z-transform?

Tip: The region of convergence is always crucial for determining the behavior and causality of the system.

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Math Problem Analysis

Mathematical Concepts

Z-transform
Region of Convergence (ROC)
Discrete-time signals

Formulas

Z-transform of a right-sided signal: Z{a^n u[n]} = 1 / (1 - az^{-1}), |z| > |a|
Z-transform of a left-sided signal: Z{a^n u[-n-1]} = 1 / (1 - az^{-1}), |z| < |a|

Theorems

Z-transform
Region of Convergence theorem

Suitable Grade Level

College/University level (Undergraduate in Signals and Systems or Digital Signal Processing)