Math Problem Statement
A sample of 106 body temperatures has a mean of 98.20oF. Assuming that the sample is random and the population standard deviation is known to be 0.62 oF. Use a 5% significance level to test that the mean body temperature of healthy adults is not 98.60 oF.
Find the test p-value. Question 4 options:
0.00
0.03
3.10
-6.64
None of the above Question 5 (Mandatory) (4 points) A sample of 106 body temperatures has a mean of 98.20oF. Assuming that the sample is random and the population standard deviation is known to be 0.62 oF. Use a 5% significance level to test that the mean body temperature of healthy adults is not 98.60 oF.
State the conclusion. Question 5 options:
Reject H0.
Do not Reject H0 (the text refer as Accept H0)
Reject Ha.
Accept Ha
None of the above
Solution
Step 1: Formulating the Hypotheses
Given that we're testing whether the mean body temperature is different from 98.60°F, we need to formulate the null and alternative hypotheses:
-
Null Hypothesis (H₀): The mean body temperature of healthy adults is 98.60°F.
-
Alternative Hypothesis (H₁): The mean body temperature of healthy adults is not 98.60°F (two-tailed test).
Step 2: Test Statistic Calculation
To test the hypothesis, we use the z-test formula because the population standard deviation () is known:
Where:
- is the sample mean.
- is the population mean under the null hypothesis.
- is the population standard deviation.
- is the sample size.
Now, substitute the values into the formula:
Let's calculate the test statistic:
Step 3: Finding the P-value
The z-value we found is approximately . For a two-tailed test, the p-value corresponds to the area under the standard normal curve that is more extreme than the absolute value of the test statistic (since the alternative hypothesis is ).
Using the z-table or a statistical tool to find the p-value corresponding to , we find that the p-value is extremely small, essentially 0.
Step 4: Decision Rule
At a significance level of , if the p-value is less than 0.05, we reject the null hypothesis.
Since the p-value is 0.00, which is less than 0.05, we reject the null hypothesis.
Conclusion
Question 4 (Test p-value):
The p-value is 0.00. Therefore, the correct answer is 0.00.
Question 5 (State the Conclusion):
Since the p-value is smaller than the significance level, we reject the null hypothesis. Therefore, the correct conclusion is:
Reject H₀.
Summary of Answers:
- Question 4: 0.00
- Question 5: Reject H₀
Would you like more details on the test calculation or any clarifications?
Here are a few related questions you might find interesting:
- How do you calculate a confidence interval for the population mean when the population standard deviation is known?
- What is the difference between a one-tailed and a two-tailed hypothesis test?
- How do you interpret a p-value of 0.03 in hypothesis testing?
- Why is it important to know whether the population standard deviation is known or not in hypothesis testing?
- What are the assumptions underlying the z-test for a population mean?
Tip: When performing hypothesis tests, always double-check if the test statistic corresponds to the correct distribution (z-test for known , t-test for unknown , etc.).
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Math Problem Analysis
Mathematical Concepts
Hypothesis Testing
Z-test
Two-Tailed Test
P-value
Formulas
z = (x̄ - μ₀) / (σ / √n)
Theorems
Central Limit Theorem
Z-test for population mean
Suitable Grade Level
Grades 11-12
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