Math Problem Statement
A data set includes 108 body temperatures of healthy adult humans having a mean of 98.2degreesF and a standard deviation of 0.64degreesF. Construct a 99% confidence interval estimate of the mean body temperature of all healthy humans. What does the sample suggest about the use of 98.6degreesF as the mean body temperature? Click here to view a t distribution table.LOADING... Click here to view page 1 of the standard normal distribution table.LOADING... Click here to view page 2 of the standard normal distribution table.LOADING... Question content area bottom Part 1 What is the confidence interval estimate of the population mean mu? enter your response heredegreesFless thanmuless than enter your response heredegreesF (Round to three decimal places as needed.)
Solution
To construct a 99% confidence interval for the mean body temperature of healthy adults, we'll use the following formula:
where:
- = sample mean = 98.2°F
- = sample standard deviation = 0.64°F
- = sample size = 108
- is the z-score corresponding to a 99% confidence level.
Step 1: Determine the z-score for a 99% Confidence Level
For a 99% confidence interval, the z-score is approximately 2.576.
Step 2: Calculate the Margin of Error (ME)
Substitute the values:
Let's calculate that:
- Calculate .
- Then, .
- Finally, .
So, the margin of error is approximately 0.159°F.
Step 3: Construct the Confidence Interval
This gives us:
Confidence Interval
Thus, the 99% confidence interval for the mean body temperature is:
Interpretation Regarding 98.6°F as a Mean Body Temperature
Since 98.6°F is outside this confidence interval, the sample suggests that the true mean body temperature of healthy humans might be lower than the traditionally accepted value of 98.6°F.
Would you like further details on any part of this calculation?
Here are some related questions to explore:
- How does sample size impact the width of a confidence interval?
- Why is a z-score used instead of a t-score in this example?
- How would the confidence interval change if the confidence level were 95% instead of 99%?
- What are the implications of finding a different mean for health-related norms?
- How does standard deviation affect the margin of error in confidence intervals?
Tip: For larger samples (n > 30), the z-score is typically used for confidence intervals, even if the population standard deviation is unknown.
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Math Problem Analysis
Mathematical Concepts
Statistics
Confidence Intervals
Standard Deviation
Z-Scores
Formulas
Confidence Interval formula: CI = x̄ ± z * (σ / √n)
Margin of Error formula: ME = z * (σ / √n)
Theorems
Central Limit Theorem (implied in large sample size)
Suitable Grade Level
Undergraduate/College Level
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