The x-intercepts of the function $y = \sin x$ on the interval $0 \leq x \leq 2\pi$ occur where $\sin x = 0$. The sine function equals zero at integer multiples of $\pi$. Thus, within the given interval, the values of $x$ that make $\sin x = 0$ are:

$x = 0, \pi, \text{ and } 2\pi$

Therefore, the correct answer is:

$0, \pi,$ and $2\pi$

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Here are 5 related questions that expand on this information:

1. What are the general x-intercepts of $y = \sin x$ outside the interval $0 \leq x \leq 2\pi$?
2. How would the x-intercepts change for the function $y = \sin(2x)$?
3. What are the x-intercepts of the function $y = \cos x$ on the interval $0 \leq x \leq 2\pi$?
4. How do the x-intercepts of $y = \sin x$ compare with those of $y = \tan x$?
5. What is the period of the function $y = \sin x$ and how does it relate to the location of the x-intercepts?

Tip: The x-intercepts of trigonometric functions often correspond to key points that can help in graphing or understanding transformations of these functions.