To find the x-intercept of the rational function $f(x) = \frac{1 - 2x}{x + 2}$, we set $f(x) = 0$ and solve for $x$.

The x-intercept occurs where the numerator equals zero:

$1 - 2x = 0$

Solving for $x$:

$2x = 1 \implies x = \frac{1}{2}$

Thus, the x-intercept of the function is at $x = \frac{1}{2}$.

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Related Questions:

1. How do you find the y-intercept of the function $f(x) = \frac{1 - 2x}{x + 2}$?
2. What is the vertical asymptote of the function $f(x) = \frac{1 - 2x}{x + 2}$?
3. How do you determine the horizontal asymptote of a rational function?
4. What is the domain of the function $f(x) = \frac{1 - 2x}{x + 2}$?
5. How do you graph the rational function $f(x) = \frac{1 - 2x}{x + 2}$?

Tip: When finding the x-intercept of a rational function, always set the numerator equal to zero and solve for $x$, provided the denominator does not become zero at that point.