Math Problem Statement

If 20% of a certain quantity of work is done by A and after that the remaining 80% of the work is done by B, the work will be completed in 20 days. If 80% of the work is done by A and after that the remaining 20% of the work is done by B, the work will be completed in 30 days. If A & B work together how many days are required to complete the work?

Solution

Let the total amount of work be 1 unit.

Case 1: 20% of the work is done by A, and 80% is done by B

  • Work done by A: 0.20.2
  • Work done by B: 0.80.8
  • Total time to complete the work: 20 days.

Let AA's rate of work be aa units/day and BB's rate of work be bb units/day.

From this, the total time can be expressed as: 0.2a+0.8b=20(1)\frac{0.2}{a} + \frac{0.8}{b} = 20 \quad \text{(1)}

Case 2: 80% of the work is done by A, and 20% is done by B

  • Work done by A: 0.80.8
  • Work done by B: 0.20.2
  • Total time to complete the work: 30 days.

From this, the total time can be expressed as: 0.8a+0.2b=30(2)\frac{0.8}{a} + \frac{0.2}{b} = 30 \quad \text{(2)}

Solving the system of equations

We now have two equations:

  1. 0.2a+0.8b=20\frac{0.2}{a} + \frac{0.8}{b} = 20
  2. 0.8a+0.2b=30\frac{0.8}{a} + \frac{0.2}{b} = 30

Let's solve these equations to find aa and bb.

Multiply equation (1) by 4 and equation (2) by 1 to simplify:

0.8a+3.2b=80(3)\frac{0.8}{a} + \frac{3.2}{b} = 80 \quad \text{(3)} 0.8a+0.2b=30(2 repeated)\frac{0.8}{a} + \frac{0.2}{b} = 30 \quad \text{(2 repeated)}

Now subtract equation (2) from equation (3):

(3.2b0.2b)=8030\left( \frac{3.2}{b} - \frac{0.2}{b} \right) = 80 - 30 3.0b=50\frac{3.0}{b} = 50 b=350=116.67units/dayb = \frac{3}{50} = \frac{1}{16.67} \, \text{units/day}

Now, substitute b=116.67b = \frac{1}{16.67} into equation (1):

0.2a+0.8116.67=20\frac{0.2}{a} + \frac{0.8}{\frac{1}{16.67}} = 20 0.2a+13.336=20\frac{0.2}{a} + 13.336 = 20 0.2a=2013.336\frac{0.2}{a} = 20 - 13.336 0.2a=6.664\frac{0.2}{a} = 6.664 a=0.26.664=133.32units/daya = \frac{0.2}{6.664} = \frac{1}{33.32} \, \text{units/day}

Working Together

When A and B work together, their combined rate is: Rate of A + B=a+b=133.32+116.67\text{Rate of A + B} = a + b = \frac{1}{33.32} + \frac{1}{16.67}

Let’s calculate the combined rate and the total number of days required to finish 1 unit of work:

1T=133.32+116.67\frac{1}{T} = \frac{1}{33.32} + \frac{1}{16.67}

Solving this, we get: T11.11days.T \approx 11.11 \, \text{days}.

Thus, if A and B work together, they will complete the work in approximately 11.11 days.

Would you like any further clarification or details?

Here are 5 questions to consider:

  1. What is the significance of the rates aa and bb in this problem?
  2. How would the solution change if A and B had different individual rates?
  3. Can you derive the solution without solving the system of equations directly?
  4. What happens if A and B start working together halfway through the project?
  5. How does the combined work rate impact overall efficiency?

Tip: When solving work-rate problems, it's often helpful to represent rates as fractions of the total work and use algebraic methods for more complex situations.

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Math Problem Analysis

Mathematical Concepts

Work and Time
Rates of Work
System of Equations

Formulas

Total work = 1 unit
Rate of A = a units/day
Rate of B = b units/day
System of equations for work completion: (Work done by A / Rate of A) + (Work done by B / Rate of B) = Total time

Theorems

Work Rate Theorem (Work = Rate × Time)

Suitable Grade Level

Grades 9-12