Math Problem Statement

Which of the following matrices has no inverse?

Solution

The question asks which of the given matrices has no inverse. A matrix has no inverse if it is singular, meaning its determinant is zero.

Let's check each matrix to see which one is singular by calculating their determinants:

  1. Matrix A: A=(2112)A = \begin{pmatrix} 2 & 1 \\ 1 & 2 \end{pmatrix} Determinant of AA: det(A)=(2)(2)(1)(1)=41=3\text{det}(A) = (2)(2) - (1)(1) = 4 - 1 = 3 Since the determinant is not zero, this matrix is invertible.

  2. Matrix B: B=(5000)B = \begin{pmatrix} 5 & 0 \\ 0 & 0 \end{pmatrix} Determinant of BB: det(B)=(5)(0)(0)(0)=0\text{det}(B) = (5)(0) - (0)(0) = 0 Since the determinant is zero, this matrix is singular (no inverse).

  3. Matrix C: C=(4284)C = \begin{pmatrix} 4 & 2 \\ 8 & 4 \end{pmatrix} Determinant of CC: det(C)=(4)(4)(2)(8)=1616=0\text{det}(C) = (4)(4) - (2)(8) = 16 - 16 = 0 Since the determinant is zero, this matrix is singular (no inverse).

  4. Matrix D: D=(0102)D = \begin{pmatrix} 0 & 1 \\ 0 & 2 \end{pmatrix} Determinant of DD: det(D)=(0)(2)(1)(0)=0\text{det}(D) = (0)(2) - (1)(0) = 0 Since the determinant is zero, this matrix is singular (no inverse).

  5. Matrix E: E=(3121)E = \begin{pmatrix} 3 & -1 \\ 2 & 1 \end{pmatrix} Determinant of EE: det(E)=(3)(1)(1)(2)=3+2=5\text{det}(E) = (3)(1) - (-1)(2) = 3 + 2 = 5 Since the determinant is not zero, this matrix is invertible.

  6. Matrix F: F=(0000)F = \begin{pmatrix} 0 & 0 \\ 0 & 0 \end{pmatrix} Determinant of FF: det(F)=(0)(0)(0)(0)=0\text{det}(F) = (0)(0) - (0)(0) = 0 Since the determinant is zero, this matrix is singular (no inverse).

  7. Matrix G: G=(6666)G = \begin{pmatrix} 6 & 6 \\ 6 & 6 \end{pmatrix} Determinant of GG: det(G)=(6)(6)(6)(6)=3636=0\text{det}(G) = (6)(6) - (6)(6) = 36 - 36 = 0 Since the determinant is zero, this matrix is singular (no inverse).

  8. Matrix H: H=(7557)H = \begin{pmatrix} 7 & 5 \\ 5 & 7 \end{pmatrix} Determinant of HH: det(H)=(7)(7)(5)(5)=4925=24\text{det}(H) = (7)(7) - (5)(5) = 49 - 25 = 24 Since the determinant is not zero, this matrix is invertible.

  9. Matrix I: I=(2222)I = \begin{pmatrix} -2 & 2 \\ 2 & 2 \end{pmatrix} Determinant of II: det(I)=(2)(2)(2)(2)=44=8\text{det}(I) = (-2)(2) - (2)(2) = -4 - 4 = -8 Since the determinant is not zero, this matrix is invertible.

  10. Matrix J: J=(1326)J = \begin{pmatrix} 1 & 3 \\ 2 & 6 \end{pmatrix} Determinant of JJ: det(J)=(1)(6)(3)(2)=66=0\text{det}(J) = (1)(6) - (3)(2) = 6 - 6 = 0 Since the determinant is zero, this matrix is singular (no inverse).

Answer:

The matrices that have no inverse are:

  • B
  • C
  • D
  • F
  • G
  • J

Would you like more details or explanations on how determinants were calculated?

Here are 5 related questions to deepen your understanding:

  1. How does the determinant help in determining whether a matrix is invertible?
  2. What is the geometric significance of a matrix with zero determinant?
  3. Can a non-square matrix have an inverse? Why or why not?
  4. How can the adjugate matrix help find the inverse of a 2x2 matrix?
  5. What is the connection between matrix rank and invertibility?

Tip: If you're solving a matrix inversion problem, always check if the determinant is zero first. This saves time in determining whether the inverse exists.

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Math Problem Analysis

Mathematical Concepts

Matrix Algebra
Linear Algebra
Matrix Determinants

Formulas

Determinant formula for 2x2 matrices: det(A) = ad - bc for matrix [[a, b], [c, d]]

Theorems

A matrix is invertible if and only if its determinant is non-zero
Singular Matrix Theorem: A matrix with a zero determinant has no inverse

Suitable Grade Level

Undergraduate or advanced high school (Grades 11-12)