It looks like you've uploaded an image containing a problem related to an operational amplifier (op-amp) circuit used in a Wheatstone bridge configuration.

Here’s a summary of the problem based on the image:

1. Task: Determine the output voltage $U_A$ as a function of the given components and values.
2. Details:
   • The circuit consists of resistances $R_1 = 22 \, \text{k}\Omega$, $R_2 = 30 \, \text{k}\Omega$, $R_3 = 3.3 \, \text{k}\Omega$, $R_4 = 1 \, \text{k}\Omega$, and $R_5 = 100 \, \Omega$.
   • The input voltage is given as $U_0 = 17 \, \text{V}$.
   • A specific condition is given where $T_1 = 30^\circ C$ and $T_2 = 80^\circ C$, suggesting temperature effects on certain components.

Steps to solve:

1. Determine the expression for the output voltage $U_A$:

   • The output voltage for an op-amp in this configuration typically follows a formula based on the voltage divider rule in the Wheatstone bridge and the gain of the amplifier.
   • The bridge balance condition (if at balance) can help simplify calculations.

2. Use the given values to calculate the output voltage for specific temperatures:

   • Substituting the resistor values and temperature conditions into the derived formula to compute $U_A$.

Do you want me to proceed with detailed calculations and explanations for the solution? If so, I can guide you through each step.

Here are 5 related questions to further expand your understanding:

1. How is the Wheatstone bridge typically used to measure resistance or other parameters?
2. What role does temperature play in affecting the resistances in a circuit like this?
3. How do you derive the output voltage of an op-amp in a Wheatstone bridge configuration?
4. What assumptions are commonly made when solving circuits with operational amplifiers?
5. How would the circuit behave if the bridge were perfectly balanced?

Tip: In Wheatstone bridges, unbalanced conditions cause a non-zero voltage across the bridge, which is amplified by the op-amp to produce the output voltage.