Steps to Build and Analyze the Wheatstone Bridge Circuit:

1. Circuit Construction:

   • Use a Wheatstone bridge configuration.
   • Place $R_1 = 1.2 \, k\Omega$, $R_3 = 1.2 \, k\Omega$, and $R_4 = 1.2 \, k\Omega$ as the fixed resistors.
   • Use a potentiometer for $R_2$, allowing its resistance to be adjusted.

2. Apply Voltage Source:

   • Connect a 6 V DC voltage source across the bridge, with one terminal at the top junction (where $R_1$ and $R_2$ meet) and the other terminal at the bottom junction (where $R_3$ and $R_4$ meet).

3. Balance the Bridge:

   • Adjust $R_2$ (the potentiometer) until the bridge is balanced. A balanced bridge is indicated by zero voltage across the galvanometer (or zero current flow through the central branch).

4. Measure $R_2$:

   • When the bridge is balanced, note the value of $R_2$.

5. Calculate the Unknown Resistance ($R_4$):

   • In a balanced Wheatstone bridge, the relationship between the resistors is: $\frac{R_1}{R_2} = \frac{R_3}{R_4}$
   • Rearrange this to find $R_4$: $R_4 = R_3 \cdot \frac{R_2}{R_1}$

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Example Calculation:

1. Suppose the potentiometer is adjusted, and $R_2$ is measured to be $1.5 \, k\Omega$ at balance.

2. Using the formula for $R_4$: $R_4 = R_3 \cdot \frac{R_2}{R_1}$ Substituting values: $R_4 = 1.2 \, k\Omega \cdot \frac{1.5 \, k\Omega}{1.2 \, k\Omega}$ Simplify: $R_4 = 1.5 \, k\Omega$

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Results:

• Measured $R_2$: $1.5 \, k\Omega$
• Calculated $R_4$: $1.5 \, k\Omega$

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Would you like further details or simulation for this setup?

Relative Questions:

1. What is the role of the potentiometer in a Wheatstone bridge?
2. Why does the bridge need to be balanced for accurate measurement?
3. How do small adjustments in $R_2$ affect the balance point?
4. Can a Wheatstone bridge be used for non-linear resistors? Why or why not?
5. What are common applications of Wheatstone bridges in real-world scenarios?

Tip:

Ensure all connections are secure and the galvanometer is properly calibrated to detect zero current for accurate balancing.