Math Problem Statement
- Is ( A \vee A ) not a wff?2. Is ( A + A ) a wff?3. Is ( A & \sim A ) a wff?4. Is ( \sim (\sim Z \supset (Z \vee Z)) ) a wff?5. Is ( (A \supset B) & (C \equiv D) \vee ((E \vee F) G) ) a wff?6. Is ( A \sim \supset (E \vee D) ) a wff?7. Is ( A \supset \sim A ) a wff?8. Is ( \sim A \supset (A \vee A) ) a wff?9. Is ( A \sim Z \supset A \vee A ) a wff?10. Is ( A \sim A \supset \sim B ) a wff?
Solution
In logic, a well-formed formula (wff) refers to a syntactically correct expression constructed according to the formal rules of the logical system. Let's analyze each of your expressions in terms of their well-formedness.
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Yes, this is a wff.
It follows the correct syntax for propositional logic where represents disjunction (OR). The same propositional variable appearing twice doesn't affect the formula's well-formedness. -
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No, this is not a wff.
The symbol is not a standard logical operator in classical propositional logic. It is more commonly used in arithmetic or boolean algebra. -
:
Yes, this is a wff.
represents conjunction (AND), and is a valid negation of . The formula is well-formed. -
:
Yes, this is a wff.
Negation , implication , and disjunction are all valid logical operators. This formula is properly constructed. -
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No, this is not a wff.
The subexpression is not well-formed because the formula should contain logical operators between propositional variables. The juxtaposition of and is syntactically incorrect. -
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No, this is not a wff.
is not a valid combination. The negation operator should precede a proposition or formula, but here it is placed between two components in an incorrect manner. -
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Yes, this is a wff.
Implication and negation are used correctly. This formula represents "if then not ." -
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Yes, this is a wff.
This formula is well-formed. It consists of a negation , implication , and a valid disjunction . -
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No, this is not a wff.
The subexpression is not valid, as should apply to a single propositional variable or formula, but here it is placed between and incorrectly. -
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No, this is not a wff.
The subexpression is not valid. As mentioned earlier, should apply to a single formula, not between two propositional variables.
In summary, the well-formed formulas (wffs) are:
Would you like more details or have any other questions?
5 Related Questions:
- What are the formal rules for constructing well-formed formulas in propositional logic?
- Can you explain the difference between logical operators like , , and ?
- What are some examples of non-wffs in propositional logic and why they fail?
- How does propositional logic differ from first-order logic in terms of wff construction?
- What role does syntax play in ensuring a formula is a wff?
Tip:
Always ensure that logical operators are applied correctly and that every part of a formula follows the syntactic rules of the logic system in use.
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Math Problem Analysis
Mathematical Concepts
Propositional Logic
Logical Connectives
Well-Formed Formula (WFF)
Formulas
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Theorems
Rules for Well-Formed Formulas in Propositional Logic
Suitable Grade Level
College/University Level Logic
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