Math Problem Statement

A committee has four members ​(Upper P 1​, Upper P 2​, Upper P 3​, and Upper P 4​). In this committee Upper P 1 has twice as many votes as Upper P 2​; Upper P 2 has twice as many votes as Upper P 3​; Upper P 3 and Upper P 4 have the same number of votes. The quota is qequals93. For each of the given definitions of the quota​, describe the committee using the notation​ [q: w1,​ w2, w3,​ w4]. ​(Hint​: Write the weighted voting system as ​[93​: ​4x, 2x,​ x, x], and then solve for​ x.) Complete parts​ (a) through​ (c) below.

Solution

Let's break down the problem step by step to describe the committee using the weighted voting system notation [q:w1,w2,w3,w4][q: w_1, w_2, w_3, w_4].

Step 1: Set up the equation

We know the following relationships between the weights (number of votes) of the members:

  • w1=4xw_1 = 4x (since P1P_1 has twice as many votes as P2P_2)
  • w2=2xw_2 = 2x (since P2P_2 has twice as many votes as P3P_3)
  • w3=xw_3 = x (since P3P_3 and P4P_4 have the same number of votes)
  • w4=xw_4 = x (since P3P_3 and P4P_4 have the same number of votes)

Thus, the weighted voting system is of the form: [93:4x,2x,x,x][93: 4x, 2x, x, x]

Step 2: Solve for xx

We now need to consider the quota q=93q = 93 given in the problem to solve for xx.

(a) When q=93q = 93

In this scenario, the equation remains: [93:4x,2x,x,x][93: 4x, 2x, x, x] But xx is arbitrary in this context since q=93q = 93 is a fixed quota, and no specific total votes are provided. Thus, we don't solve for xx directly as we don't have the total number of votes specified.

So, the notation for the committee remains: [93:4x,2x,x,x][93: 4x, 2x, x, x]

(b) When q=34q = \frac{3}{4} of total votes

Here, we need to find the total number of votes and set the quota q=34q = \frac{3}{4} of the total votes. The total number of votes VV is: V=4x+2x+x+x=8xV = 4x + 2x + x + x = 8x

So, the quota qq is: q=34×8x=6xq = \frac{3}{4} \times 8x = 6x

Thus, the weighted voting system becomes: [6x:4x,2x,x,x][6x: 4x, 2x, x, x]

(c) When q=12q = \frac{1}{2} of total votes

Similarly, for this case, the quota qq is: q=12×8x=4xq = \frac{1}{2} \times 8x = 4x

So, the weighted voting system is: [4x:4x,2x,x,x][4x: 4x, 2x, x, x]

Summary of Answers:

  • (a) q=93q = 93: The committee is described as [93:4x,2x,x,x][93: 4x, 2x, x, x].
  • (b) q=34q = \frac{3}{4} of total votes: The committee is described as [6x:4x,2x,x,x][6x: 4x, 2x, x, x].
  • (c) q=12q = \frac{1}{2} of total votes: The committee is described as [4x:4x,2x,x,x][4x: 4x, 2x, x, x].

Would you like any further details or have any questions about these solutions?

Related Questions:

  1. How does the change in the quota affect the voting power of each committee member?
  2. What happens if qq is greater than the total number of votes?
  3. How would the system change if P1P_1 had three times as many votes as P2P_2?
  4. Can P3P_3 or P4P_4 ever have veto power in these setups?
  5. How can we calculate

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Math Problem Analysis

Mathematical Concepts

Algebra
Weighted Voting Systems
Proportions

Formulas

Total votes V = 4x + 2x + x + x = 8x
Quota for 3/4 of total votes: q = 6x
Quota for 1/2 of total votes: q = 4x

Theorems

Proportionality

Suitable Grade Level

Grades 9-12