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The answer is **10 cm of water** because we are measuring the pressure difference between two points in a water manometer, which depends on the height difference between the water columns. Here's how it's calculated:

- The height of water on the left side of the manometer is **17 cm**.
- The height of water on the right side of the manometer is **15 cm**.

To find the pressure difference, we need the difference in water levels between the two sides:
\[
\text{Height difference} = 17 \, \text{cm} - 7 \, \text{cm} = 10 \, \text{cm}.
\]

Thus, the pressure of the gas supply is **10 cm of water** greater than atmospheric pressure, as represented by the difference in height between the two sides.

If the difference were only **2 cm**, it would imply that the two water levels are very close to each other, which they are not. The 10 cm difference represents the actual pressure difference due to the gas supply.

Would you like further details or have any other questions?

Here are 5 follow-up questions you might consider:
1. How do water manometers work to measure pressure differences?
2. Why does the height difference in water relate directly to pressure?
3. What is the relation between water pressure and other units like Pascal or mmHg?
4. Can this same method be used for gases other than air, like hydrogen or methane?
5. How would temperature changes affect the water levels in a manometer?

**Tip**: In fluid mechanics, pressure differences in manometers are proportional to the height difference in the liquid columns.

This problem explains why the pressure difference in a water manometer is 10 cm of water rather than 2 cm. It involves fluid mechanics and the calculation of pressure difference based on the height of water columns. Suitable for high school students learning about pressure measurements.

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