Mr. Gill is draining his pool. The pump he is using changes the water level by -2 1/4
 
 inches per hour. A stronger pump would drain the pool 2 1/2
 
 times as fast. What would the change in water level be per hour if Mr. Gill used the stronger pump?

To find the change in water level per hour if Mr. Gill used the stronger pump, we need to multiply the current drainage rate by the factor of 2 1/2 (which is 2.5).

### Current drainage rate:
\[
-2 \frac{1}{4} \text{ inches per hour} = -\frac{9}{4} \text{ inches per hour}
\]

### Stronger pump rate (2 1/2 times faster):
Multiply the current rate by 2.5:
\[
\text{New rate} = -\frac{9}{4} \times 2.5
\]

First, convert 2.5 to a fraction:
\[
2.5 = \frac{5}{2}
\]

Now multiply:
\[
\text{New rate} = -\frac{9}{4} \times \frac{5}{2} = -\frac{45}{8} \text{ inches per hour}
\]

### Conclusion:
The change in water level would be \(-\frac{45}{8}\) inches per hour, or approximately \(-5.625\) inches per hour if Mr. Gill used the stronger pump.

Would you like further explanation or any additional details?

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Here are 5 related questions:
1. How would the rate change if the pump drained 3 times as fast?
2. What would the total water level change be after 4 hours with the stronger pump?
3. How do you multiply mixed numbers and fractions efficiently?
4. How much faster is 2 1/2 times compared to 1 1/4 times?
5. What if the original rate were different, like \(-3 \frac{1}{2}\) inches per hour?

**Tip:** When multiplying mixed numbers, always convert them to improper fractions first for easier calculation.

Mr. Gill is draining his pool. The pump he is using changes the water level by -2 1/4 inches per hour. A stronger pump would drain the pool 2 1/2 times as fast. What would the change in water level be per hour if Mr. Gill used the stronger pump?

Find out how to calculate the new water level change per hour when using a stronger pump. In this math problem, Mr. Gill's current pump drains the pool at -2 1/4 inches per hour, and the stronger pump works 2 1/2 times as fast. The solution involves multiplying mixed numbers and converting them into improper fractions. This problem is perfect for students in Grades 5-7.

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