a 15 ft. deep swimming pool was drained and was empty after 3 hours. if it was drained at a steady rate what integer represents how many feet per hour the water decreased?

To find out how many feet per hour the water level in the swimming pool decreased, we need to determine the rate of decrease given that the pool was emptied in 3 hours.

The pool is **15 feet deep**, and it was drained completely over **3 hours**. The rate of decrease can be calculated by dividing the total depth by the time taken:

\[
\text{Rate of decrease} = \frac{\text{Total depth}}{\text{Time}}
\]

Substitute the given values:

\[
\text{Rate of decrease} = \frac{15 \, \text{ft}}{3 \, \text{hours}}
\]

Now, perform the division:

\[
\text{Rate of decrease} = 5 \, \text{feet per hour}
\]

So, the integer representing how many feet per hour the water decreased is **5 feet per hour**.

Would you like more details or have any questions?

Here are some related questions:
1. What would be the rate if the pool was drained in 5 hours?
2. How long would it take to drain a pool twice as deep at the same rate?
3. What is the volume of water drained if the pool has a surface area of 200 square feet?
4. How can we express this draining rate in inches per minute?
5. How do different drainage rates affect pool maintenance?

**Tip:** To find the rate of change in a situation like this, divide the total change by the time taken.

Learn how to calculate the rate of decrease of a swimming pool that was drained at a steady rate, resulting in an empty pool after 3 hours. Understand the mathematical concept of rate of change and division. Suitable for middle school students (Grades 6-8).

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