Math Problem Statement
. A cuboid of base area P sq units is filled with water upto a height of Q units. A sphere of volume R cu units is dropped into the cuboid such that it is completely submerged. A representation of the submerged sphere is shown below.
Solution
To understand this problem clearly, we need to analyze the situation step by step.
Given:
- Cuboid with a base area of square units.
- Water filled up to a height of units.
- Sphere of volume cubic units is completely submerged in the water inside the cuboid.
Objective:
We need to determine the effect of the sphere being submerged into the cuboid. Typically, this results in water displacement and a rise in the water level within the cuboid.
Approach:
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Water initially in the cuboid: The volume of water already in the cuboid before the sphere is submerged can be found by: where is the base area, and is the initial height of water.
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Volume of the sphere: The volume of the sphere is given by cubic units.
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New height of water after submersion: After the sphere is submerged, the water level will rise due to the displacement of water. The displaced water volume equals the volume of the sphere, . Let the new height of water in the cuboid be .
The new volume of water in the cuboid is:
Since the additional volume of water is due to the sphere, the total volume of water after submersion is the initial water volume plus the sphere's volume:
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Solving for the new height: Rearranging the equation to solve for :
Result:
After the sphere is submerged, the new height of the water in the cuboid will be:
This equation shows that the new water height increases by , which is the volume of the sphere divided by the base area of the cuboid.
Would you like further details or clarifications?
Here are 5 related questions to consider:
- How would the result change if the cuboid had a slanted side?
- What happens if the sphere isn't completely submerged?
- How would the water height change if multiple spheres are submerged?
- How can we calculate the volume of a sphere given its radius?
- How can this problem be generalized to irregular shapes?
Tip: When working with volumes and areas, always ensure the units are consistent across the problem.
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Math Problem Analysis
Mathematical Concepts
Volume
Water Displacement
Geometry
Algebra
Formulas
V = P × Q
H = Q + R / P
Theorems
Principle of Archimedes (displacement of water)
Suitable Grade Level
Grades 9-11
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