Math Problem Statement
The solid with a semicircular base of radius 11 whose cross sections perpendicular to the base and parallel to the diameter are squares. find volune
Solution
To find the volume of a solid with a semicircular base of radius 11, whose cross-sections perpendicular to the base and parallel to the diameter are squares, we can use the following method:
Step-by-Step Approach:
-
Equation of the semicircle:
Since the base is a semicircle, the equation of the semicircle (with radius ) in the -plane is: where ranges from to . -
Area of the cross-section:
The cross-sections perpendicular to the base and parallel to the diameter are squares. The side length of each square is equal to the height of the semicircle at a given , which is .Therefore, the area of the square at a particular is:
-
Volume by integration:
To find the total volume, we integrate the area of the square cross-sections along the base of the semicircle from to : -
Evaluate the integral:
We can break the integral into two parts: The first integral is straightforward: The second integral is: Since the term is an even function, the integral over symmetric limits cancels out to zero.Therefore, the total volume is:
Thus, the volume of the solid is 10,648 cubic units.
Would you like further details on any of these steps?
Here are five related questions for further exploration:
- What is the formula for finding volumes of solids with different cross-sectional shapes?
- How would the volume change if the base were a full circle rather than a semicircle?
- Can this method be applied to cross-sections that are equilateral triangles instead of squares?
- How does the shape of the base affect the volume of a solid?
- What happens if the radius of the semicircular base is doubled?
Tip: When dealing with volume problems, always check if you can simplify the cross-sectional area function to make integration easier.
Ask a new question for Free
By Image
Drop file here or Click Here to upload
Math Problem Analysis
Mathematical Concepts
Geometry
Calculus
Volume of Solids of Revolution
Formulas
Equation of semicircle: y = sqrt(121 - x^2)
Area of cross-section: A(x) = 4(121 - x^2)
Volume by integration: V = ∫ from -11 to 11 (484 - 4x^2) dx
Theorems
Method of Cross-Sections
Integral Calculus
Suitable Grade Level
Grades 11-12, College Level Calculus
Related Recommendation
Volume of a Solid with a Semicircular Base and Square Cross Sections
Volume of Solid with Semicircular Base and Square Cross Sections
Volume of Solid with Square Cross-Sections and Semicircular Base
Finding the Volume of a Solid with a Semicircular Base and Square Cross Sections
Volume of Solid with Semicircular Cross-Sections Bounded by y = x^3