Math Problem Statement

Find the volume of the solid obtained by rotating the region bounded by the curve ( y = \sqrt{x} ), the x-axis, and the line ( x = 4 ) about the y-axis.

Solution

To find the volume of the solid obtained by rotating the region bounded by the curve y=xy = \sqrt{x}, the x-axis, and the line x=4x = 4 about the y-axis, we use the method of cylindrical shells.

Step 1: Express xx in terms of yy

Given the curve y=xy = \sqrt{x}, we first solve for xx in terms of yy: y=x    x=y2y = \sqrt{x} \implies x = y^2

Step 2: Set up the volume integral using the shell method

The formula for the volume of a solid of revolution using the method of cylindrical shells is: V=2πab(radius)×(height)dyV = 2\pi \int_{a}^{b} ( \text{radius} ) \times (\text{height}) \, dy

  • Radius: The radius of a cylindrical shell is the distance from the axis of rotation (the y-axis), which is simply x=y2x = y^2.
  • Height: The height of the cylindrical shell is given by the function x=y2x = y^2, ranging from y=0y = 0 to y=2y = 2 (since y=xy = \sqrt{x} and x=4x = 4).

The volume integral becomes: V=2π02y×y2dyV = 2\pi \int_{0}^{2} y \times y^2 \, dy V=2π02y3dyV = 2\pi \int_{0}^{2} y^3 \, dy

Step 3: Evaluate the integral

To evaluate the integral, first compute the antiderivative of y3y^3: y3dy=y44\int y^3 \, dy = \frac{y^4}{4}

Now, apply the limits of integration from 0 to 2: V=2π[y44]02V = 2\pi \left[ \frac{y^4}{4} \right]_{0}^{2} V=2π(244044)V = 2\pi \left( \frac{2^4}{4} - \frac{0^4}{4} \right) V=2π(164)=2π×4=8πV = 2\pi \left( \frac{16}{4} \right) = 2\pi \times 4 = 8\pi

Final Answer

The volume of the solid is 8π\boxed{8\pi} cubic units.

Would you like more details or have any questions?

Here are some related questions for further practice:

  1. How would the volume change if the region were rotated about the x-axis instead?
  2. What is the volume if the region is rotated about the line x=6x = 6 instead of the y-axis?
  3. How would you find the surface area of the solid formed by rotating the same region about the y-axis?
  4. What if the curve was y=x2y = x^2 instead of y=xy = \sqrt{x}? How would the volume change?
  5. How does the volume calculation differ if the boundary is extended to x=9x = 9?

Tip: The shell method is particularly useful when the solid of revolution involves a function that is easier to express in terms of the radius and height relative to the axis of rotation.

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Math Problem Analysis

Mathematical Concepts

Solid of Revolution
Cylindrical Shells Method

Formulas

Volume of a solid of revolution using cylindrical shells

Theorems

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Suitable Grade Level

Advanced High School