Math Problem Statement

The base of a certain solid is an equilateral triangle with altitude 9. Cross-sections perpendicular to the altitude are semicircles. Find the volume of the solid, using the formulaV=∫abA(x), with the left vertex of the triangle at the origin and the given altitude along the x-axis.

Solution

To find the volume of the solid using the given information, we can follow these steps:

Step 1: Determine the equation of the base

The base of the solid is an equilateral triangle with an altitude of 9 units. Since the triangle is equilateral, the length of each side can be determined using the formula for the height (altitude) of an equilateral triangle:

Height=32×side length\text{Height} = \frac{\sqrt{3}}{2} \times \text{side length}

Given that the height is 9, we can solve for the side length ss:

9=32s9 = \frac{\sqrt{3}}{2} s

s=183=63s = \frac{18}{\sqrt{3}} = 6\sqrt{3}

Since the altitude lies along the xx-axis and the left vertex of the triangle is at the origin, the vertices of the triangle are located at (0,0)(0, 0), (9,0)(9, 0), and (92,63)\left(\frac{9}{2}, 6\sqrt{3}\right).

Step 2: Determine the function for the base width

The width of the triangle at any height xx from the base (at x=0x = 0) can be determined by the line equation. The length of the side perpendicular to the altitude at a distance xx from the base is given by:

[ \text{Width}(x) = 2 \times \text{length of the segment from the center to the edge}

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Math Problem Analysis

Mathematical Concepts

Geometry
Calculus
Solid Geometry

Formulas

Volume of solid V = ∫[a,b] A(x) dx
Height of an equilateral triangle h = (sqrt(3)/2) * side length
Area of semicircle A = (1/2) * π * r^2

Theorems

Integral Calculus
Geometric Properties of Equilateral Triangles

Suitable Grade Level

Grades 11-12