The volume $V$ of a sphere is given by the formula:

$V = \frac{4}{3} \pi r^3$

where $r$ is the radius of the sphere. You provided that the radius $r = 16$ and we use $\pi \approx 3.14$.

Let's calculate the volume:

$V = \frac{4}{3} \times 3.14 \times (16)^3$

First, calculate $16^3$:

$16^3 = 16 \times 16 \times 16 = 4096$

Now, calculate the volume:

$V = \frac{4}{3} \times 3.14 \times 4096 = \frac{4 \times 3.14 \times 4096}{3}$

$V = \frac{4 \times 3.14 \times 4096}{3} = \frac{51337.28}{3} \approx 17112.43$

So, the volume of the sphere is approximately 17,112.43 cubic units.

Let me know if you'd like further clarification!

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Related questions:

1. How does changing the radius of a sphere affect its volume?
2. Can you derive the volume formula for a sphere from first principles?
3. How do you calculate the surface area of a sphere?
4. What would the volume of the sphere be if the radius was doubled?
5. How does the use of an approximation for $\pi$ affect the accuracy of the volume?

Tip: When approximating, always check if you need to round at intermediate steps or only at the final answer!