Math Problem Statement

Find the volume of the solid formed when the region bounded by f(x) = x^2 * sqrt(16 - x^2) and the x-axis on 0 <= x <= 4 is revolved about the y-axis. Graph of region shown.

Solution

To find the volume of the solid formed when the given region is revolved about the y-axis, we will use the method of cylindrical shells. The equation of the curve is:

f(x)=x216x2f(x) = x^2 \sqrt{16 - x^2}

We are rotating the region bounded by this function and the x-axis over the interval 0x40 \leq x \leq 4.

Step-by-Step Solution Using the Method of Cylindrical Shells:

The volume of a solid of revolution using the method of cylindrical shells is given by:

V=2πabxf(x)dxV = 2\pi \int_{a}^{b} x f(x) \, dx

Here, xx represents the radius of a typical shell, f(x)f(x) is the height of the shell, and [a,b][a, b] is the interval over which we are integrating.

Step 1: Identify the bounds and function

  • The function is f(x)=x216x2f(x) = x^2 \sqrt{16 - x^2}.
  • The bounds are a=0a = 0 and b=4b = 4.

Step 2: Set up the integral

We will now set up the integral for the volume:

V=2π04x(x216x2)dxV = 2\pi \int_{0}^{4} x \left( x^2 \sqrt{16 - x^2} \right) dx

Simplifying the integrand:

V=2π04x316x2dxV = 2\pi \int_{0}^{4} x^3 \sqrt{16 - x^2} \, dx

Step 3: Substitution for the integral

Let u=16x2u = 16 - x^2, then du=2xdxdu = -2x \, dx.

This substitution simplifies the integral:

  • When x=0x = 0, u=16u = 16.
  • When x=4x = 4, u=0u = 0.

Thus, the integral becomes:

V=2π16012(16u)uduV = 2\pi \int_{16}^{0} -\frac{1}{2} (16 - u) \sqrt{u} \, du

We can now calculate this integral to find the volume of the solid.

I will solve the integral now.The volume of the solid formed by revolving the region around the y-axis is:

V=4096π15 cubic units.V = \frac{4096\pi}{15} \text{ cubic units}.

This is the exact value of the volume.

Would you like further clarification or details?

Here are 5 related questions to expand on this:

  1. How does the method of cylindrical shells differ from the disk/washer method for finding volumes?
  2. What is the physical meaning of the term 2πxf(x)dx2\pi \int x \cdot f(x) \, dx in this context?
  3. How can you apply a similar method to revolve the region around the x-axis instead?
  4. How would the integral change if the region were rotated around a different line, such as x=2x = 2?
  5. How can you visualize the solid created by this revolution?

Tip: Always check if your function is symmetric when applying integration techniques. Symmetry can simplify the calculation.

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Math Problem Analysis

Mathematical Concepts

Integral Calculus
Volumes of Solids of Revolution
Cylindrical Shells Method

Formulas

V = 2 * pi * integral(a to b) of x * f(x) dx
Substitution: u = 16 - x^2, du = -2x dx

Theorems

Method of Cylindrical Shells

Suitable Grade Level

College-level Calculus