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The problem asks for the volume of a cylindrical pipe with a radius of 2 feet and a length (height) of 23 feet, using \( \pi = 3.14 \).

### Formula for the volume of a cylinder:
\[
V = \pi r^2 h
\]
Where:
- \( V \) is the volume,
- \( r \) is the radius,
- \( h \) is the height (or length),
- \( \pi \) is approximately 3.14.

### Given values:
- Radius \( r = 2 \) feet,
- Height \( h = 23 \) feet,
- \( \pi = 3.14 \).

### Step-by-step solution:
1. Square the radius:
   \[
   r^2 = 2^2 = 4
   \]
2. Multiply by \( \pi \) and the height:
   \[
   V = 3.14 \times 4 \times 23
   \]
3. Calculate the product:
   \[
   V = 3.14 \times 92 = 288.88
   \]

Rounding to the nearest whole number:
\[
V \approx 289 \text{ cubic feet}.
\]

The volume of the cylindrical pipe is approximately **289 ft³**.

Would you like more details or have any questions?

Here are five related questions to expand on this:

1. How would the volume change if the radius doubled?
2. How do you calculate the surface area of this cylinder?
3. What if the pipe length increased by 10 feet? How would the volume change?
4. What would happen to the volume if the radius were halved but the length stayed the same?
5. How is the volume of a cone calculated, and how does it relate to the volume of a cylinder?

**Tip**: When working with cylinders, always check that you're using the radius (not the diameter) in volume calculations!

The radius of a cylindrical construction pipe is 2 ft. If the pipe is 23 ft long, what is its volume? Use the value 3.14 for π, and round your answer to the nearest whole number.

Learn how to calculate the volume of a cylindrical construction pipe with a radius of 2 feet and a length of 23 feet. This detailed solution includes the volume formula for a cylinder and key steps to calculate the result.

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