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The problem asks to calculate the volume of a cylindrical construction pipe, with the following given values:
- Radius (\(r\)) = 2.5 feet
- Height (\(h\)) = 23 feet
- Use \( \pi = 3.14 \)

The formula for the volume of a cylinder is:

\[
V = \pi r^2 h
\]

Substituting the given values:

\[
V = 3.14 \times (2.5)^2 \times 23
\]

Now let's calculate the volume.The volume of the cylindrical pipe is approximately 451 cubic feet (\( \text{ft}^3 \)).

Would you like more details or have any questions? Here are some related questions you might find useful:

1. How would the volume change if the radius were doubled?
2. What is the surface area of this cylindrical pipe?
3. How can we calculate the mass of the pipe if the material density is provided?
4. What is the relationship between volume and radius in a cylinder?
5. How would the volume change if the height of the cylinder were halved?

**Tip:** Remember that the volume of a cylinder is directly proportional to both the square of the radius and the height. Doubling the radius has a more significant impact than doubling the height!

The radius of a cylindrical construction pipe is 2.5 ft. If the pipe is 23 ft long, what is its volume?

Learn how to calculate the volume of a cylindrical construction pipe with a radius of 2.5 feet and a height of 23 feet. This problem demonstrates key concepts in geometry, including the formula for the volume of a cylinder (V = πr²h), and is suitable for students in Grades 6-8.

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