Math Problem Statement
Solution
This is a circuit analysis problem. We are asked to find the potential difference (voltage drop) across the 2-ohm resistor () in the circuit. Here's how we can proceed step-by-step:
Step 1: Identify the configuration of the circuit.
- There are two voltage sources: and .
- The resistors , , and are connected in a combination of series.
Step 2: Combine the resistors.
The three resistors are in series, so the total resistance is the sum of all resistances:
Step 3: Calculate the total voltage.
The two voltage sources are in series, so the total voltage is the sum of the two voltages:
Step 4: Find the total current in the circuit.
Using Ohm's law, , the total current flowing through the circuit is:
Step 5: Calculate the voltage drop across the 2-ohm resistor.
The voltage drop across can be calculated using Ohm's law, , where is the current and is the resistance. Thus, the voltage across is:
Final Answer:
The potential difference (voltage drop) across the 2-ohm resistor is 5 V.
Would you like further details on this calculation or any clarification?
Related Questions:
- How do you calculate the total resistance in a parallel circuit?
- What is the difference between series and parallel circuits?
- How do you apply Kirchhoff's Voltage Law to this type of circuit?
- How do you calculate the power dissipated by the 2-ohm resistor?
- What happens if one of the voltage sources is removed in this circuit?
Tip:
When dealing with circuits, always check whether the components are connected in series or parallel, as this greatly affects how you sum resistances and calculate the total current.
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Math Problem Analysis
Mathematical Concepts
Circuit Analysis
Ohm's Law
Series Circuits
Formulas
Ohm's Law: V = IR
Total Resistance in Series: R_total = R1 + R2 + R3
Total Voltage: V_total = ε1 + ε2
Current: I_total = V_total / R_total
Theorems
Ohm's Law
Kirchhoff's Voltage Law (for series circuits)
Suitable Grade Level
Grades 10-12
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