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The problem asks how to shift the graph of \( y = x^2 \) to obtain the graph of \( f(x) = x^2 + 13 \).

The function \( f(x) = x^2 + 13 \) is a vertical translation of the basic parabola \( y = x^2 \). The \( +13 \) causes the graph to shift **up by 13 units**. Therefore, the correct answer is to shift the graph of \( y = x^2 \) up by **13 units**.

Let me know if you need further details or have any other questions! 

Here are some related questions:
1. How would you shift \( y = x^2 \) to graph \( f(x) = x^2 - 5 \)?
2. What happens to the graph if you add a negative constant to \( x^2 \)?
3. How do you shift \( y = x^2 \) horizontally to the left or right?
4. What would the graph of \( f(x) = 2x^2 + 13 \) look like?
5. How does the graph change if you subtract 13 instead of adding it?

**Tip:** A vertical shift occurs when a constant is added or subtracted to the whole function.

To graph the function f(x) = x^2 + 13, shift the graph of y = x^2 up how many units?

Learn how to graph the function f(x) = x^2 + 13 by shifting the basic parabola y = x^2. Understand the concept of vertical shifts and how adding a constant to a function affects its graph. Suitable for Grades 9-10.

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