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We are asked to find the equations of the vertical and horizontal lines that pass through the point \( (6, -2) \).

1. **Equation of the vertical line**:
   - A vertical line has the form \( x = \text{constant} \), and the constant is the x-coordinate of the point it passes through. 
   - Since the point is \( (6, -2) \), the x-coordinate is 6.
   - Therefore, the equation of the vertical line is:
     \[
     x = 6
     \]

2. **Equation of the horizontal line**:
   - A horizontal line has the form \( y = \text{constant} \), and the constant is the y-coordinate of the point it passes through.
   - The y-coordinate of the point is -2.
   - Therefore, the equation of the horizontal line is:
     \[
     y = -2
     \]

### Summary:
- **Vertical line**: \( x = 6 \)
- **Horizontal line**: \( y = -2 \)

Let me know if you need further details or explanations!

### Related Questions:
1. What is the general equation for a line in slope-intercept form?
2. How do you find the slope of a vertical line?
3. What is the difference between vertical and horizontal lines in terms of slope?
4. How can you find the equation of a line through two points?
5. Can a line be both vertical and horizontal? If yes, in which case?

### Tip:
The slope of a vertical line is undefined, while the slope of a horizontal line is always zero.

Write the equations of the vertical and horizontal lines through the point (6, -2).

Learn how to find the equations of the vertical and horizontal lines passing through the point (6, -2). This problem covers key concepts from coordinate geometry, including the forms of vertical and horizontal lines.

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