What is the vertex of  y=(X+2)squared +1
 


The equation you provided is:

\[
y = (x + 2)^2 + 1
\]

This is in the **vertex form** of a quadratic equation, which is generally written as:

\[
y = a(x - h)^2 + k
\]

where \((h, k)\) is the vertex of the parabola.

In your equation, comparing it to the general form:

- \(h = -2\)
- \(k = 1\)

Therefore, the vertex of the parabola is:

\[
\boxed{(-2, 1)}
\]

Would you like more details on how this form works or have any other questions?

### Related Questions:
1. How do you convert a standard quadratic equation into vertex form?
2. What is the significance of the vertex in a quadratic graph?
3. How do you determine if the vertex represents a maximum or a minimum point?
4. What effect does changing the value of \(a\) in \(y = a(x - h)^2 + k\) have on the graph?
5. How would you find the axis of symmetry for a quadratic equation?

**Tip:** The vertex form of a quadratic equation is useful for quickly identifying the maximum or minimum point on the graph!

Learn how to find the vertex of the quadratic equation y = (x + 2)^2 + 1. This problem explains key algebraic concepts, including the vertex form of quadratic functions, and is ideal for students in Grades 8-10.

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