The vertex of the graph of y = (x - 1)2 - 5 is

The equation of the parabola is given as \( y = (x - 1)^2 - 5 \).

This is in vertex form, \( y = a(x - h)^2 + k \), where:

- \( (h, k) \) is the vertex of the parabola,
- \( a \) determines the direction and the width of the parabola.

In this case:
- \( h = 1 \),
- \( k = -5 \).

Thus, the vertex of the parabola is \( (1, -5) \).

Would you like further details or have any questions?

Here are 5 related questions to deepen your understanding:

1. How do you convert a quadratic equation from standard form to vertex form?
2. What is the effect of the value of \( a \) in the vertex form of a parabola?
3. How do you find the axis of symmetry from the vertex form of a quadratic equation?
4. How do you determine whether the vertex is a maximum or minimum point?
5. How can you find the x-intercepts and y-intercepts of the parabola?

**Tip:** The vertex form is particularly useful for quickly identifying the maximum or minimum point of a parabola and its axis of symmetry.

The vertex of the graph of y = (x - 1)^2 - 5 is

Discover how to find the vertex of the quadratic equation y = (x - 1)^2 - 5 using the vertex form. This problem helps you identify the vertex and understand the impact of the equation's parameters. Suitable for students in Grades 8-10.

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