Math Problem Statement

\nabla \times(\psi \hat{\mathbf{k}})=(\operatorname{grad} \psi) \times \hat{\mathbf{k}}

Solution

Let's break down this vector calculus equation step by step:

Goal:

To verify or interpret the expression:

×(ψk^)=(gradψ)×k^\nabla \times (\psi \hat{\mathbf{k}}) = (\operatorname{grad} \psi) \times \hat{\mathbf{k}}

where:

  • ×\nabla \times is the curl operator,
  • ψ\psi is a scalar field,
  • k^\hat{\mathbf{k}} is the unit vector in the zz-direction,
  • gradψ=ψ\operatorname{grad} \psi = \nabla \psi is the gradient of ψ\psi.

The Left-Hand Side (LHS): ×(ψk^)\nabla \times (\psi \hat{\mathbf{k}})

Using the vector calculus identity: ×(fA)=(f)×A+f(×A),\nabla \times (f \mathbf{A}) = (\nabla f) \times \mathbf{A} + f (\nabla \times \mathbf{A}), where ff is a scalar field (ψ\psi) and A\mathbf{A} is a vector (k^\hat{\mathbf{k}}), we calculate:

  1. First term: (ψ)×k^(\nabla \psi) \times \hat{\mathbf{k}}.

    • Here, ψ\nabla \psi is the gradient of the scalar field ψ\psi, which gives a vector.
  2. Second term: ψ(×k^)\psi (\nabla \times \hat{\mathbf{k}}).

    • The curl of k^\hat{\mathbf{k}} is zero because k^\hat{\mathbf{k}} is a constant unit vector (its components do not depend on position).

Thus: ×(ψk^)=(ψ)×k^.\nabla \times (\psi \hat{\mathbf{k}}) = (\nabla \psi) \times \hat{\mathbf{k}}.


The Right-Hand Side (RHS): (gradψ)×k^(\operatorname{grad} \psi) \times \hat{\mathbf{k}}

This is simply a rephrasing of the term (ψ)×k^(\nabla \psi) \times \hat{\mathbf{k}}, as gradψ=ψ\operatorname{grad} \psi = \nabla \psi by definition.


Conclusion:

The equation is correct: ×(ψk^)=(gradψ)×k^.\nabla \times (\psi \hat{\mathbf{k}}) = (\operatorname{grad} \psi) \times \hat{\mathbf{k}}.

This is consistent with the vector calculus identity used earlier.


Let me know if you'd like further clarifications or a worked example!

Related Questions:

  1. What is the physical interpretation of the curl operator in vector calculus?
  2. How is the curl of a vector field related to fluid dynamics?
  3. Can this result be extended to any arbitrary unit vector (not just k^\hat{\mathbf{k}})?
  4. What is the divergence of the vector field ψk^\psi \hat{\mathbf{k}}?
  5. How do you calculate the gradient, divergence, and curl in cylindrical coordinates?

Tip:

Always check if vector components (like k^\hat{\mathbf{k}}) are constant or spatially varying; this simplifies the application of vector calculus identities.

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Math Problem Analysis

Mathematical Concepts

Vector Calculus
Curl Operator
Gradient
Vector Identities

Formulas

\nabla \times (f \mathbf{A}) = (\nabla f) \times \mathbf{A} + f (\nabla \times \mathbf{A})
\nabla \psi = \operatorname{grad} \psi

Theorems

Curl and Scalar Multiplication Identity

Suitable Grade Level

Undergraduate (Calculus III or Vector Calculus)