To draw the velocity vs. time graph based on the given position-time graph, we need to analyze the slope of each segment of the graph, as the velocity is the rate of change of position with respect to time.

Step-by-step breakdown:

1. From $t = 0$ to $t = 1$ second:

   • The graph rises from 1 meter to 2 meters.
   • Slope $\frac{\Delta s}{\Delta t} = \frac{2 - 1}{1 - 0} = 1 \, \text{m/s}$.
   • So, velocity = $1 \, \text{m/s}$.

2. From $t = 1$ to $t = 2$ seconds:

   • The graph remains flat (horizontal line at 2 meters).
   • Slope = 0, meaning the object is not moving.
   • So, velocity = $0 \, \text{m/s}$.

3. From $t = 2$ to $t = 3$ seconds:

   • The graph decreases from 2 meters to 1 meter.
   • Slope $\frac{\Delta s}{\Delta t} = \frac{1 - 2}{3 - 2} = -1 \, \text{m/s}$.
   • So, velocity = $-1 \, \text{m/s}$.

4. From $t = 3$ to $t = 5$ seconds:

   • The graph remains flat (horizontal line at 1 meter).
   • Slope = 0, meaning the object is stationary again.
   • So, velocity = $0 \, \text{m/s}$.

5. From $t = 5$ to $t = 6$ seconds:

   • The graph rises from 1 meter to 5 meters.
   • Slope $\frac{\Delta s}{\Delta t} = \frac{5 - 1}{6 - 5} = 4 \, \text{m/s}$.
   • So, velocity = $4 \, \text{m/s}$.

Velocity vs. Time Plot:

• From $t = 0$ to $t = 1$ second: $v = 1 \, \text{m/s}$.
• From $t = 1$ to $t = 2$ seconds: $v = 0 \, \text{m/s}$.
• From $t = 2$ to $t = 3$ seconds: $v = -1 \, \text{m/s}$.
• From $t = 3$ to $t = 5$ seconds: $v = 0 \, \text{m/s}$.
• From $t = 5$ to $t = 6$ seconds: $v = 4 \, \text{m/s}$.

Would you like me to draw the velocity-time graph based on this information?