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The image you've provided shows a question about a "Horizontal Velocity-Time Graph" where the slope and intercept values are given as 0 m/s². This suggests that the velocity is constant over time, meaning there is no acceleration (since the slope is the acceleration in a velocity-time graph).

In such a scenario, the equation for velocity \( v(x) \) would be:

\[
v(x) = 0 \, \text{m/s}
\]

This is because both the slope (representing acceleration) and intercept (initial velocity) are zero, indicating that the object is stationary.

Would you like further details or have any specific questions?

Here are 5 related questions to think about:
1. What would the graph look like for a non-zero slope?
2. How would a non-zero intercept affect the equation?
3. What does a zero slope imply about the forces acting on the cart?
4. Can velocity change without acceleration?
5. How would you experimentally determine the slope and intercept?

**Tip**: In a velocity-time graph, the area under the curve represents the displacement of the object.

Write the numerical fit values for your Horizontal Velocity-Time graph from logger pro. Slope: 0 m/s², intercept: 0 m/s². Use these numerical fit values to write your specific equation for the velocity of your cart in proper form including units.

Understand how to interpret a velocity-time graph with a slope and intercept of 0 m/s². This problem explains the concept of constant velocity and provides the specific velocity equation for the cart, ideal for students in Grades 9-12.

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