To solve for the vector B - A, we need to consider both the magnitudes and directions of vectors A and B.

Step 1: Express the vectors in component form.

• A is directed along the positive x-axis and has a magnitude of 3.00 units. Therefore, the vector A in component form is: $\mathbf{A} = +3.00 \, \hat{i}$

• B is directed along the negative x-axis and has a magnitude of 2.00 units. Therefore, the vector B in component form is: $\mathbf{B} = -2.00 \, \hat{i}$

Step 2: Subtract vectors (B - A).

Now, subtract vector A from vector B: $\mathbf{B} - \mathbf{A} = (-2.00 \, \hat{i}) - (+3.00 \, \hat{i})$ $\mathbf{B} - \mathbf{A} = -2.00 \, \hat{i} - 3.00 \, \hat{i} = -5.00 \, \hat{i}$

Step 3: Analyze the result.

The resulting vector has a magnitude of 5.00 units and is directed along the negative x-axis.

Final Answer:

The magnitude and direction of vector B - A is: $\boxed{5.00 \, \text{units in the negative x direction.}}$

Let me know if you would like further details or clarifications!

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Here are 5 related questions for practice:

1. What would be the result of A - B instead of B - A?
2. How would the result change if vector A had a magnitude of 4 units?
3. What is the resultant vector if A is directed along the y-axis instead of the x-axis?
4. How do you find the magnitude of a vector in 2D space?
5. What happens to the magnitude of a vector if both vectors are doubled?

Tip: When subtracting vectors, always pay close attention to the directions, as they are as important as magnitudes in vector calculations.