Math Problem Statement

The probability distribution of the random variable X is given in the following table. Find Var(X). (Round your answer to 4 decimal places.)

x

1

2

3

4

5

P(X =x)

0.12

0.24

0.36

0.17

0.11

Solution

To find the variance Var(X)\text{Var}(X) of a discrete random variable XX, we need to follow these steps:

Step 1: Calculate the expected value E(X)E(X).

The expected value is calculated as: E(X)=(xiP(X=xi))E(X) = \sum (x_i \cdot P(X = x_i)) where xix_i are the possible values of XX and P(X=xi)P(X = x_i) are the corresponding probabilities.

From the table: E(X)=(10.12)+(20.24)+(30.36)+(40.17)+(50.11)E(X) = (1 \cdot 0.12) + (2 \cdot 0.24) + (3 \cdot 0.36) + (4 \cdot 0.17) + (5 \cdot 0.11) E(X)=0.12+0.48+1.08+0.68+0.55=2.91E(X) = 0.12 + 0.48 + 1.08 + 0.68 + 0.55 = 2.91

Step 2: Calculate E(X2)E(X^2).

To find E(X2)E(X^2), we first square the xx-values and then multiply by their respective probabilities: E(X2)=(xi2P(X=xi))E(X^2) = \sum (x_i^2 \cdot P(X = x_i)) E(X2)=(120.12)+(220.24)+(320.36)+(420.17)+(520.11)E(X^2) = (1^2 \cdot 0.12) + (2^2 \cdot 0.24) + (3^2 \cdot 0.36) + (4^2 \cdot 0.17) + (5^2 \cdot 0.11) E(X2)=(10.12)+(40.24)+(90.36)+(160.17)+(250.11)E(X^2) = (1 \cdot 0.12) + (4 \cdot 0.24) + (9 \cdot 0.36) + (16 \cdot 0.17) + (25 \cdot 0.11) E(X2)=0.12+0.96+3.24+2.72+2.75=9.79E(X^2) = 0.12 + 0.96 + 3.24 + 2.72 + 2.75 = 9.79

Step 3: Calculate the variance Var(X)\text{Var}(X).

The variance is given by: Var(X)=E(X2)(E(X))2\text{Var}(X) = E(X^2) - (E(X))^2 Var(X)=9.79(2.91)2=9.798.4681=1.3219\text{Var}(X) = 9.79 - (2.91)^2 = 9.79 - 8.4681 = 1.3219

So, the variance of XX is Var(X)=1.3219\text{Var}(X) = 1.3219.

Would you like more details on any step, or do you have any questions?

Relative questions:

  1. How is the standard deviation related to variance?
  2. What are the properties of a probability distribution?
  3. How do you find the expected value of a continuous random variable?
  4. What is the significance of variance in statistics?
  5. Can you explain how the law of large numbers relates to expected value?

Tip:

Remember, variance measures how spread out the values of a random variable are from the mean.

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Math Problem Analysis

Mathematical Concepts

Probability
Statistics
Expected Value
Variance

Formulas

E(X) = Σ (x_i * P(X = x_i))
E(X^2) = Σ (x_i^2 * P(X = x_i))
Var(X) = E(X^2) - (E(X))^2

Theorems

Expected Value Theorem
Variance Formula

Suitable Grade Level

Grades 10-12