Math Problem Statement

Prove that \( \binom{m+n}{r} = \sum_{k=0}^{r} \binom{m}{k} \binom{n}{r-k} \)

Solution

The problem requires proving the following identity involving binomial coefficients:

(m+nr)=k=0r(mk)(nrk)\binom{m+n}{r} = \sum_{k=0}^{r} \binom{m}{k} \binom{n}{r-k}

Proof Using Combinatorial Argument:

This identity is often referred to as the "Vandermonde Convolution" and can be proven using a combinatorial argument.

Step-by-step Proof:

  1. Combinatorial Interpretation:

    • The left-hand side, (m+nr)\binom{m+n}{r}, represents the number of ways to choose rr elements from a set of m+nm+n elements.
    • Consider the set as the union of two disjoint subsets: one of size mm and the other of size nn.
  2. Breaking Down the Selection:

    • To choose rr elements from m+nm+n, we can break it down into choosing kk elements from the first subset (size mm) and the remaining rkr-k elements from the second subset (size nn).
  3. Counting the Ways:

    • The number of ways to choose kk elements from the first subset is given by (mk)\binom{m}{k}.
    • The number of ways to choose rkr-k elements from the second subset is given by (nrk)\binom{n}{r-k}.
  4. Applying the Multiplication Principle:

    • For each kk, the total number of ways to choose kk elements from the first subset and rkr-k elements from the second subset is the product (mk)(nrk)\binom{m}{k} \binom{n}{r-k}.
  5. Summing Over All Possible Values of kk:

    • Since kk can range from 0 to rr, we sum over all possible values of kk to count all possible ways to choose rr elements from m+nm+n:

    k=0r(mk)(nrk).\sum_{k=0}^{r} \binom{m}{k} \binom{n}{r-k}.

  6. Conclusion:

    • This is exactly the expression on the right-hand side of the given identity. Hence, the identity is proven:

    (m+nr)=k=0r(mk)(nrk).\binom{m+n}{r} = \sum_{k=0}^{r} \binom{m}{k} \binom{n}{r-k}.

This completes the proof using a combinatorial argument.

Would you like to see more detailed steps, or do you have any specific questions?

Related Questions:

  1. What is the binomial theorem, and how is it related to binomial coefficients?
  2. How can this identity be used in probability theory or statistics?
  3. Can this identity be proven using algebraic methods instead of combinatorial arguments?
  4. What are other combinatorial identities involving binomial coefficients?
  5. How does Vandermonde's identity extend to multinomial coefficients?

Tip:

When dealing with combinatorial identities, try interpreting them in terms of choosing elements from sets or subsets. This approach often provides an intuitive proof.

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Math Problem Analysis

Mathematical Concepts

Combinatorics
Binomial Coefficients
Summation

Formulas

Vandermonde's Identity: \( \binom{m+n}{r} = \sum_{k=0}^{r} \binom{m}{k} \binom{n}{r-k} \)
Binomial Coefficient: \( \binom{n}{k} = \frac{n!}{k!(n-k)!} \)

Theorems

Vandermonde's Convolution

Suitable Grade Level

Undergraduate level (or advanced high school students)