Math Problem Statement

Suppose rank(A) = number of columns of A. Which of the statements is always true?

Solution

The question asks about the least squares solution, focusing on the matrix AA where rank(A)=number of columns of A\text{rank}(A) = \text{number of columns of } A. This implies that AA has full column rank, meaning ATAA^T A is invertible.

In least squares problems, the solution to Ax=bA x = b in the over-determined case (more equations than unknowns) is given by x=(ATA)1ATbx = (A^T A)^{-1} A^T b. This formula represents the unique least squares solution because ATAA^T A is invertible.

Correct Answer:

The second option: A(ATA)1ATb is the unique least square solution to Ax=b.A(A^T A)^{-1} A^T b \text{ is the unique least square solution to } Ax = b. is always true in this case.

Would you like a detailed explanation or have any specific questions? Here are five related questions to consider:

  1. What does it mean for a matrix to have full column rank?
  2. Why is ATAA^T A invertible when rank(A)=number of columns of A\text{rank}(A) = \text{number of columns of } A?
  3. What is the difference between a least squares solution and an exact solution?
  4. How is the least squares solution derived from normal equations?
  5. What happens to the least squares solution if ATAA^T A is not invertible?

Tip: In least squares problems, the projection Au=bA u = b implies that the solution minimizes the error Axb\| A x - b \|.

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Math Problem Analysis

Mathematical Concepts

Linear Algebra
Least Squares
Matrix Inversion

Formulas

(A^T A)^{-1} A^T b
Normal equations A^T A x = A^T b

Theorems

Least Squares Solution Theorem
Full Rank Matrix Theorem

Suitable Grade Level

University Level (Linear Algebra)