Math Problem Statement

Diketahui A = {x | x^2 - 1 = 0}, B = {x | x^2 + x - 2 = 0}, dan C = {x | x^3 - x^2 = 0}. Tentukan: a. A ∪ (B ∩ C); b. (A ∪ B) ∩ C; dan c. (A - B) ∪ C.

Solution

Let's solve this step-by-step.

We are given three sets:

  1. Set A: A={xx21=0}A = \{ x \mid x^2 - 1 = 0 \}
  2. Set B: B={xx2+x2=0}B = \{ x \mid x^2 + x - 2 = 0 \}
  3. Set C: C={xx3x2=0}C = \{ x \mid x^3 - x^2 = 0 \}

Step 1: Determine the elements of each set

Set A: x21=0x^2 - 1 = 0

This can be factored as: x21=(x1)(x+1)=0x^2 - 1 = (x - 1)(x + 1) = 0 So, x=1x = 1 or x=1x = -1.

Thus, A={1,1}A = \{ -1, 1 \}.

Set B: x2+x2=0x^2 + x - 2 = 0

This can be factored as: x2+x2=(x+2)(x1)=0x^2 + x - 2 = (x + 2)(x - 1) = 0 So, x=2x = -2 or x=1x = 1.

Thus, B={2,1}B = \{ -2, 1 \}.

Set C: x3x2=0x^3 - x^2 = 0

This can be factored as: x3x2=x2(x1)=0x^3 - x^2 = x^2(x - 1) = 0 So, x=0x = 0 or x=1x = 1.

Thus, C={0,1}C = \{ 0, 1 \}.

Step 2: Calculate the required set operations

Part (a): A(BC)A \cup (B \cap C)

  1. Find BCB \cap C:

    • B={2,1}B = \{ -2, 1 \}
    • C={0,1}C = \{ 0, 1 \}
    • The intersection BC={1}B \cap C = \{ 1 \}.
  2. Now find A(BC)A \cup (B \cap C):

    • A={1,1}A = \{ -1, 1 \}
    • BC={1}B \cap C = \{ 1 \}
    • The union A(BC)={1,1}A \cup (B \cap C) = \{ -1, 1 \}.

So, A(BC)={1,1}A \cup (B \cap C) = \{ -1, 1 \}.

Part (b): (AB)C(A \cup B) \cap C

  1. Find ABA \cup B:

    • A={1,1}A = \{ -1, 1 \}
    • B={2,1}B = \{ -2, 1 \}
    • The union AB={2,1,1}A \cup B = \{ -2, -1, 1 \}.
  2. Now find (AB)C(A \cup B) \cap C:

    • AB={2,1,1}A \cup B = \{ -2, -1, 1 \}
    • C={0,1}C = \{ 0, 1 \}
    • The intersection (AB)C={1}(A \cup B) \cap C = \{ 1 \}.

So, (AB)C={1}(A \cup B) \cap C = \{ 1 \}.

Part (c): (AB)C(A - B) \cup C

  1. Find ABA - B:

    • A={1,1}A = \{ -1, 1 \}
    • B={2,1}B = \{ -2, 1 \}
    • The difference AB={1}A - B = \{ -1 \} (since 1 is in both A and B).
  2. Now find (AB)C(A - B) \cup C:

    • AB={1}A - B = \{ -1 \}
    • C={0,1}C = \{ 0, 1 \}
    • The union (AB)C={1,0,1}(A - B) \cup C = \{ -1, 0, 1 \}.

So, (AB)C={1,0,1}(A - B) \cup C = \{ -1, 0, 1 \}.

Summary of Results

  • (a) A(BC)={1,1}A \cup (B \cap C) = \{ -1, 1 \}
  • (b) (AB)C={1}(A \cup B) \cap C = \{ 1 \}
  • (c) (AB)C={1,0,1}(A - B) \cup C = \{ -1, 0, 1 \}

Would you like further details on any part of this solution?

Related Questions

  1. How do you find the intersection and union of two sets?
  2. What are some common methods for factoring polynomials?
  3. How can you visualize set operations with Venn diagrams?
  4. How does the complement of a set affect union and intersection results?
  5. Can we apply similar methods to solve inequalities involving set notation?

Tip

Always double-check your factorizations and solutions for each set to ensure accuracy in set operations.

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Math Problem Analysis

Mathematical Concepts

Set Theory
Algebra
Factoring Polynomials

Formulas

Quadratic equation x^2 - 1 = 0
Quadratic equation x^2 + x - 2 = 0
Cubic equation x^3 - x^2 = 0

Theorems

Union and Intersection of Sets
Set Difference

Suitable Grade Level

Grades 10-12