You're correct in pointing out that \(\sqrt{7}\) isn't a whole number. However, it does exist as an irrational number. The square root of 7 (\(\sqrt{7}\)) is an irrational number that approximately equals 2.64575. 

In this problem, you're supposed to order all the numbers from least to greatest, including \(\sqrt{7}\) even though it's an irrational number. Here's the revised ordering explanation:

1. **\(\frac{2}{3}\)** = \(0.6666...\) (approximately 0.67)
2. **2.2** (already a decimal)
3. **\(\sqrt{4}\)** = 2 (since \(\sqrt{4} = 2\))
4. **\(\sqrt{7}\)** ≈ 2.64575
5. **2.3** (already a decimal)

So, from least to greatest, the correct order is:

\[
\frac{2}{3}, \sqrt{4}, 2.2, 2.3, \sqrt{7}
\]

Would you like any more details or explanations? 

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**Related questions:**
1. What is the approximate value of \(\sqrt{2}\)?
2. How can you determine if a number is irrational?
3. What is the square root of 9? 
4. How can you simplify square roots?
5. What is the difference between rational and irrational numbers?

**Tip:** Remember that square roots of non-perfect squares (like \(\sqrt{7}\)) are irrational numbers and cannot be exactly expressed as fractions or decimals.

Explore the concept of the square root of 7, an irrational number, with detailed explanations and examples. Learn about irrational numbers and their representation as decimals. Suitable for students in Grades 6-8.

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