Math Problem Statement
Let A={modulus x:x belongs to R}, B{x:x belongs to R} then
Solution
Let's analyze the given sets and :
-
Set :
This set represents all possible values of the modulus (absolute value) of real numbers. Since the modulus of any real number is always non-negative, the set includes all non-negative real numbers: -
Set :
This set represents all real numbers. Therefore:
Comparing the Sets and :
-
Subset Relation:
- Clearly, every element of (which is non-negative) is also an element of (which includes all real numbers). Therefore, .
- However, not every element of is in , since includes negative numbers, which are not in . Hence, .
-
Equality:
- The sets and are not equal because only contains non-negative numbers, whereas contains both negative and positive numbers.
So, the relationship between and is: is a proper subset of .
Would you like any further details or have any questions?
Here are five related questions you could explore:
- What is the union of sets and in this context?
- How would the set change if defined as , where is the set of integers?
- What is the intersection of sets and ?
- Can you define a set such that ?
- How would the set look if it were defined as ?
Tip: When working with sets, especially when defining them in terms of properties like modulus, always consider the range of possible values to understand the subset and equality relationships.
Ask a new question for Free
By Image
Drop file here or Click Here to upload
Math Problem Analysis
Mathematical Concepts
Set theory
Formulas
-
Theorems
-
Suitable Grade Level
Advanced
Related Recommendation
Intersection of Sets A and B in Real Numbers
Proof of Set Theory: Understanding Set Operations A and B
Understanding Set Theory: Properties of Set Operations Explained
Understanding Subsets and Intervals in Set Theory: Analyzing Sets A, B, and C
Understanding Set Theory and Inequalities with Greatest Integer Function and Exponential Functions