Math Problem Statement

Let A={modulus x:x belongs to R}, B{x:x belongs to R} then

Solution

Let's analyze the given sets AA and BB:

  • Set AA: A={x:xR}A = \{ |x| : x \in \mathbb{R} \}
    This set represents all possible values of the modulus (absolute value) of real numbers. Since the modulus of any real number xx is always non-negative, the set AA includes all non-negative real numbers: A=[0,)A = [0, \infty)

  • Set BB: B={x:xR}B = \{ x : x \in \mathbb{R} \}
    This set represents all real numbers. Therefore: B=(,)B = (-\infty, \infty)

Comparing the Sets AA and BB:

  1. Subset Relation:

    • Clearly, every element of AA (which is non-negative) is also an element of BB (which includes all real numbers). Therefore, ABA \subseteq B.
    • However, not every element of BB is in AA, since BB includes negative numbers, which are not in AA. Hence, B⊈AB \not\subseteq A.
  2. Equality:

    • The sets AA and BB are not equal because AA only contains non-negative numbers, whereas BB contains both negative and positive numbers.

So, the relationship between AA and BB is: ABA \subset B AA is a proper subset of BB.

Would you like any further details or have any questions?

Here are five related questions you could explore:

  1. What is the union of sets AA and BB in this context?
  2. How would the set AA change if defined as A={x:xZ}A = \{ |x| : x \in \mathbb{Z} \}, where Z\mathbb{Z} is the set of integers?
  3. What is the intersection of sets AA and BB?
  4. Can you define a set CC such that BCB \subset C?
  5. How would the set AA look if it were defined as A={x:x[0,1]}A = \{ |x| : x \in [0, 1] \}?

Tip: When working with sets, especially when defining them in terms of properties like modulus, always consider the range of possible values to understand the subset and equality relationships.