Math Problem Statement
when bringing x to one side from '-5x-2=x^2+2' i did: -x^2-5x-4=0. I then factorised this and got -(x-4)(x-1)=0. Thus, when finding the final two values i ended up ignoring the rule of inverting the operation sign in the brackets because there was already a negative sign on the outside of the bracket. Can I be correct in doing this?
Solution
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Math Problem Analysis
Mathematical Concepts
Quadratic Equations
Factorization
Formulas
Quadratic equation ax^2 + bx + c = 0
Factorization of quadratic equations
Theorems
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Suitable Grade Level
Grades 9-12