Math Problem Statement

2(x²+x)=5

Solution

To rewrite the equation 2(x2+x)=52(x^2 + x) = 5 in the standard form ax2+bx+c=0ax^2 + bx + c = 0, follow these steps:

Step 1: Expand and Distribute

Distribute the 2 across the terms inside the parentheses: 2(x2+x)=2x2+2x2(x^2 + x) = 2x^2 + 2x So, the equation becomes: 2x2+2x=52x^2 + 2x = 5

Step 2: Move All Terms to One Side

Subtract 5 from both sides to set the equation equal to 0: 2x2+2x5=02x^2 + 2x - 5 = 0

Step 3: Identify the Coefficients

Now the equation is in the standard form ax2+bx+c=0ax^2 + bx + c = 0, where:

  • a=2a = 2
  • b=2b = 2
  • c=5c = -5

So, the equation in standard form is: 2x2+2x5=02x^2 + 2x - 5 = 0

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Related Questions

  1. How can you solve the quadratic equation 2x2+2x5=02x^2 + 2x - 5 = 0?
  2. What are the methods to factorize quadratic equations?
  3. How do you calculate the roots of a quadratic equation using the quadratic formula?
  4. What is the significance of the discriminant in solving quadratic equations?
  5. How do you complete the square for the equation 2x2+2x5=02x^2 + 2x - 5 = 0?
  6. How can you graph the quadratic equation 2x2+2x5=02x^2 + 2x - 5 = 0?
  7. What are the axis of symmetry and vertex of the quadratic equation?
  8. Can you solve a quadratic equation by substitution or elimination methods?

Tip

When moving all terms to one side, always ensure the quadratic equation is set to zero; this is key for applying various solving methods.

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Math Problem Analysis

Mathematical Concepts

Algebra
Quadratic Equations

Formulas

Quadratic equation standard form ax^2 + bx + c = 0

Theorems

Quadratic formula

Suitable Grade Level

Grades 9-12