Math Problem Statement
回答4-7
Solution
Let's solve questions 4 to 7 step by step.
Question 4:
If and are positive integers for which:
- is odd
then
This statement is True. It is a direct application of Euler's theorem which states that if , then for any integer that is coprime with .
Question 5:
Given with . Check all that apply.
Let's examine each statement:
-
Using Fermat's Little Theorem: for any integer and a prime , we get: This statement is True.
-
We need to see if the product is congruent to . Simplifying this, we note that: Since , we have: This statement is True.
-
is a complete residue system A complete residue system modulo 71 would contain every integer from 0 to 70 exactly once. Since is , it will cycle through all residues because and are coprime, thus covering every residue exactly once. This statement is True.
Question 6:
If is an odd prime and is a positive integer for which , then .
This statement is True. Since , for some integer . Therefore: By Fermat's Little Theorem, and . Therefore, .
Question 7:
If and are odd primes, then .
This statement is True. It follows from Euler's theorem. For , we use . Euler's theorem tells us: Since and is one less than , it satisfies the theorem.
Would you like more details on any of these questions or have any further questions? Here are five more questions you might be interested in:
- How can Euler's theorem be applied to cryptography?
- What is Fermat's Little Theorem and how is it used?
- How can we determine if a set forms a complete residue system?
- What are the properties of modular arithmetic?
- Can you provide examples of calculating modular exponentiation?
Tip:
Understanding the principles of modular arithmetic and number theory can greatly simplify solving problems involving congruences and the Euler's totient function.
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Math Problem Analysis
Mathematical Concepts
Number Theory
Modular Arithmetic
Euler's Theorem
Fermat's Little Theorem
Formulas
Fermat's Little Theorem: a^(p-1) ≡ 1 (mod p)
Theorems
Euler's Theorem
Suitable Grade Level
Advanced High School
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