The table you've uploaded represents the motion of an object with constant acceleration, where the acceleration $|a|$ is given as $10 \, \text{m/s}^2$. The columns show time ($t$) in seconds, velocity ($|v|$) in meters per second, and the corresponding displacement ($|\Delta y|$) in meters.

Let's break it down:

• $|a| = 10 \, \text{m/s}^2$: This represents the magnitude of the acceleration.
• Time (t): Starts at $0 \, \text{s}$ and increases in increments of 1 second, up to 10 seconds.
• Velocity ($|v|$): Starts at $50 \, \text{m/s}$, decreases until it reaches $0 \, \text{m/s}$ at $t = 5 \, \text{s}$, and then increases again. This suggests a change in direction at $t = 5 \, \text{s}$, which is when the velocity reaches zero.
• Displacement ($|\Delta y|$): Shows the distance the object has traveled at each time interval. Initially, the object is slowing down, and after $t = 5 \, \text{s}$, the displacement increases again as the object accelerates in the opposite direction.

The motion described in the table suggests uniformly accelerated motion, such as free fall or motion under a constant force.

Would you like further details or clarifications?

Here are five related questions to deepen understanding:

1. How is the velocity at each time step calculated from acceleration?
2. Why does the velocity decrease to zero and then increase again?
3. How can we calculate the total displacement of the object over the entire 10 seconds?
4. What is the relationship between the change in displacement and velocity at each time interval?
5. How does the graph of velocity versus time look for this motion?

Tip: The area under a velocity vs. time graph gives the displacement over a time interval.