Let's analyze the questions step by step using the graph provided.

Part 1: Acceleration at 1 Second

Question: What is the acceleration at 1 second?
Answer in units of m/s².

Solution:

• Acceleration is given by the change in velocity over time.
• From the graph, at 1 second, the velocity changes from 0 m/s at $t = 0$ to 6 m/s at $t = 2$ seconds.
• The acceleration between $t = 0$ and $t = 2$ is $\frac{\Delta v}{\Delta t} = \frac{6 \, \text{m/s} - 0 \, \text{m/s}}{2 \, \text{s} - 0 \, \text{s}} = 3 \, \text{m/s}^2$.
• Since the interval between 0 and 2 seconds is uniform, the acceleration at 1 second is also $3 \, \text{m/s}^2$.

Part 2: Velocity at 2 Seconds

Question: What is the velocity at 2 seconds?
Answer in units of m/s.

Solution:

• From the graph, the velocity at $t = 2$ seconds is 6 m/s.

Part 3: Position at 2 Seconds

Question: What is the position at 2 seconds?
Answer in units of m.

Solution:

• The position can be found by calculating the area under the velocity-time graph between 0 and 2 seconds.
• The area under the graph from 0 to 2 seconds forms a triangle.
• The area of the triangle is $\text{Area} = \frac{1}{2} \times \text{base} \times \text{height} = \frac{1}{2} \times 2 \, \text{s} \times 6 \, \text{m/s} = 6 \, \text{m}$.
• The initial position is given as 10 m. Therefore, the position at 2 seconds is $10 \, \text{m} + 6 \, \text{m} = 16 \, \text{m}$.

Summary of Answers:

1. Acceleration at 1 second: 3 m/s².
2. Velocity at 2 seconds: 6 m/s.
3. Position at 2 seconds: 16 m.

Would you like further details or have any questions?

Here are 5 related questions to expand your understanding:

1. What is the acceleration at 4 seconds?
2. How does the velocity change between 4 and 6 seconds?
3. What is the total displacement by the end of 9 seconds?
4. Calculate the acceleration between 6 and 9 seconds.
5. What is the velocity at 7 seconds?

Tip: When working with velocity-time graphs, remember that the area under the curve represents the displacement.