Math Problem Statement

First mean value theorem statement

Solution

The Mean Value Theorem (MVT) states that if a function ff is continuous on the closed interval [a,b][a, b] and differentiable on the open interval (a,b)(a, b), then there exists at least one point cc in the interval (a,b)(a, b) such that:

f(c)=f(b)f(a)ba.f'(c) = \frac{f(b) - f(a)}{b - a}.

In other words, the instantaneous rate of change (the derivative) at some point cc is equal to the average rate of change of the function over the interval [a,b][a, b].

Conditions for the theorem to apply:

  1. ff is continuous on [a,b][a, b].
  2. ff is differentiable on (a,b)(a, b).

This theorem guarantees that the slope of the tangent line at some point cc is equal to the slope of the secant line connecting the endpoints (a,f(a))(a, f(a)) and (b,f(b))(b, f(b)).

Would you like more details or have any questions?

Here are some related questions:

  1. What is the geometric interpretation of the Mean Value Theorem?
  2. How is the Mean Value Theorem applied in real-world problems?
  3. What is the difference between the Mean Value Theorem and Rolle's Theorem?
  4. Can the Mean Value Theorem be extended to vector-valued functions?
  5. What are some common counterexamples where the Mean Value Theorem does not apply?

Tip: Remember that differentiability implies continuity, but continuity does not necessarily imply differentiability.

Ask a new question for Free

By Image

Drop file here or Click Here to upload

Math Problem Analysis

Mathematical Concepts

Calculus
Mean Value Theorem

Formulas

f'(c) = \frac{f(b) - f(a)}{b - a}

Theorems

Mean Value Theorem

Suitable Grade Level

Advanced High School and Above